All categories

1 year ago

At which point does the water in the waterfall have the greatest gravitational potential energy?

Chemistry

2 answers:

VashaNatasha [74]1 year ago

7 0

Answer:

Explanation:

becuase the GPE is at its highest since when thr water falls its gravity

Dimas [21]1 year ago

3 0

Answer:

At the top of the waterfall

Explanation:

You might be interested in

The movement of atoms molecules waves and electrons is

nikdorinn [45]

Energy, I think, haven't done that since 8th grade

4 0

3 years ago

Isoniazid is used in the treatment of tuberculosis and multiple sclerosis. Identify each lone pair as either localized or deloca

dolphi86 [110]

Answer:

Please find the complete question and its solution in the attached file:

Explanation:

4 0

2 years ago

How can a change to another population could affect births and deaths in the parrot population.

forsale [732]

Answer:

read it first

Explanation:

Population change is governed by the balance between birth rates and death rates. If the birth rate stays the same and the death rate decreases, then population numbers will grow. If the birth rate increases and the death rate stays the same, then population will also grow.

hope it helps

6 0

1 year ago

What should go in the blank?

dem82 [27]

Answer:

³⁸₂₀Ca.

Explanation:

³⁸₁₉K –> __ + ⁰₋₁β

Let ʸₓA represent the unknown.

Thus the equation above can be written as:

³⁸₁₉K –> ʸₓA + ⁰₋₁β

Thus, we can obtain the value of y an x as follow:

38 = y + 0

y = 38

19 = x + (–1)

19 = x – 1

Collect like terms

19 + 1 = x

x = 20

Thus,

ʸₓA => ³⁸₂₀A => ³⁸₂₀Ca

Therefore, the equation is:

³⁸₁₉K –> ³⁸₂₀Ca + ⁰₋₁β

6 0

2 years ago

A 0.2722 g sample of a pure carbonate, X n CO 3 ( s ) , was dissolved in 50.0 mL of 0.1200 M HCl ( aq ) . The excess HCl ( aq )

Alex73 [517]

Answer:

0.00369 moles of HCl react with carbonate.

Explanation:

Number of moles of HCl present initially = $\frac{0.1200}{1000}\times 50.0$ moles = 0.00600 moles

Neutralization reaction (back titration): $NaOH+HCl\rightarrow NaCl+H_{2}O$

According to above equation, 1 mol of NaOH reacts with 1 mol of 1 mol of HCl.

So, excess number of moles of HCl present = number of NaOH added for back titration = $\frac{0.0980}{1000}\times 23.60$ moles = 0.00231 moles

So, mole of HCl reacts with carbonate = (Number of moles of HCl present initially) - (excess number of moles of HCl present) = (0.00600 - 0.00231) moles = 0.00369 moles

Hence, 0.00369 moles of HCl react with carbonate.

3 0

2 years ago