Question

Two point charges, q1 and q2, are separated by a distance r. if the magnitudes of both charges are doubled and their separation is also doubled, what happens to the electrical force that each charge exerts on the other one?

Answer 1

It will stay the same. Electric force decreases with distance but increases with magnitude of charge. By doubling them both, they essentially cancel out and nothing changes

Answer 2

Answer:

The electrical force that each charge exerts on the other one will be same .

Explanation:

Given that,

Two point charges, q₁ and q₂, are separated by a distance r.

The electric force will be

$F = \dfrac{kq_{1}q_{2}}{r^2}$

If the magnitudes of both charges are doubled and their separation is also doubled.

The new electric force will be

$F' = \dfrac{k\times2\times q_{1}\times2\times q_{2}}{(2r)^2}$

$F'=\dfrac{kq_{1}q_{2}}{r^2}$

$F'=F$

Therefore, We can say that the new electric force F' will be same as the electric force F.

Hence, The electrical force that each charge exerts on the other one will be same .