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Alekssandra [29.7K]
3 years ago
12

Two point charges, q1 and q2, are separated by a distance r. if the magnitudes of both charges are doubled and their separation

is also doubled, what happens to the electrical force that each charge exerts on the other one?
Physics
2 answers:
Svet_ta [14]3 years ago
5 0
It will stay the same. Electric force decreases with distance but increases with magnitude of charge. By doubling them both, they essentially cancel out and nothing changes
omeli [17]3 years ago
4 0

Answer:

The electrical force that each charge exerts on the other one will be same .

Explanation:

Given that,

Two point charges, q₁ and q₂, are separated by a distance r.

The electric force will be

F = \dfrac{kq_{1}q_{2}}{r^2}

If the magnitudes of both charges are doubled and their separation is also doubled.

The new electric force will be

F' = \dfrac{k\times2\times q_{1}\times2\times q_{2}}{(2r)^2}

F'=\dfrac{kq_{1}q_{2}}{r^2}

F'=F

Therefore, We can say that the new electric force F' will be same as the electric force F.

Hence, The electrical force that each charge exerts on the other one will be same .

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where I_{rms} is the rms current and I_0 is the maximum current.

If we re-arrange the formula and we use I_{rms}=7.75 A, we can find the value of the maximum current:
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A 75 lb weight hangs from a string as shown in the figure. Find the tensions T1 and T2 in the string.
fomenos
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below is the solution:

<span>T2cos(30) - T1cos(50) = 0
</span><span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span><span>T2cos(30) - T1cos(50) = 0 --> T1 = T2cos(30)/cos(50)
</span>
<span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span>(<span>T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 --> Solve for T2

</span><span>T1 = -T1cos(50)i + T1sin(50)j
T2 = T2cos(30)i + T2sin(3)j
</span>
<span>(T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 --> T2[(cos(30)/cos(50))sin(50) + sin(30)] = 75*(grav) --> T2 = 75*grav/ [(cos(30)/cos(50))sin(50) + sin(30)]
</span>
<span> T2 = 1566.49 </span>
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