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vazorg [7]
3 years ago
7

1. An atom that loses electrons has a ________________________ charge and an atom that gains

Physics
1 answer:
JulsSmile [24]3 years ago
3 0
I’ll start you off

1. Positive, negative, ions

Answer a few yourself and I’ll come back and help some more.
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How does the input distance of a single fixed pulley compare to the out- put distance?
ololo11 [35]

A pulley is another sort of basic machine in the lever family. We may have utilized a pulley to lift things, for example, a banner on a flagpole.

<u>Explanation:</u>

The point in a fixed pulley resembles the support of a lever. The remainder of the pulley behaves like the fixed arm of a first-class lever, since it rotates around a point. The distance from the fulcrum is the equivalent on the two sides of a fixed pulley. A fixed pulley has a mechanical advantage of one. Hence, a fixed pulley doesn't increase the force.

It essentially alters the direction of the force. A moveable pulley or a mix of pulleys can deliver a mechanical advantage of more than one. Moveable pulleys are appended to the item being moved. Fixed and moveable pulleys can be consolidated into a solitary unit to create a greater mechanical advantage.

4 0
3 years ago
Friction is defined as *
den301095 [7]

Answer:

O a force that opposes motion

5 0
3 years ago
a race car driver achieved a speed of 53m/s in 14 seconds after taking off from rest from the starting line. what was the averag
Veronika [31]

Answer:

53/14

Explanation:

average acceleration = (Vfinal -Vintial)/ time taken

3 0
3 years ago
Read 2 more answers
An airplane is flying through a thundercloud at a height of 2000 m (This is a very dangerous thing to do because of updrafts, tu
Doss [256]

Answer:

400000\ \text{N/C}

Explanation:

q_1 = Charge at 3000 m = 40 C

q_2 = Charge at 1000 m = -40 C

r_1 = 3000 m

r_2 = 1000 m

k = Coulomb constant = 9\times10^9\ \text{Nm}^2/\text{C}^2

Electric field due to the charge at 3000 m

E_1=\dfrac{k|q_1|}{r_1^2}\\\Rightarrow E_1=\dfrac{9\times 10^9\times 40}{3000^2}\\\Rightarrow E_1=40000\ \text{N/C}

Electric field due to the charge at 1000 m

E_2=\dfrac{k|q_2|}{r_2^2}\\\Rightarrow E_2=\dfrac{9\times 10^9\times 40}{1000^2}\\\Rightarrow E_2=360000\ \text{N/C}

Electric field at the aircraft is E_1+E_2=40000+360000=400000\ \text{N/C}.

7 0
3 years ago
A 95 kg clock initially at rest on a horizontal floor requires a 650 n horizontal force to set it in motion. after the clock is
Tamiku [17]
The μs between the clock and floor is 650(M*g) and the μk between the clock and the floor is 560(M*g)
3 0
3 years ago
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