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Alenkinab [10]
3 years ago
11

A 0.155 kg arrow is shot upward

Physics
2 answers:
solniwko [45]3 years ago
3 0

Answer:

2.43J

Explanation:

Given parameters:

Mass of the arrow = 0.155kg

Velocity = 31.4m /s

Unknown:

Kinetic energy when it leaves the bow = ?

Solution:

The kinetic energy of a body is the energy in motion of the body;

 it can be derived using the expression below:

 

   K.E  = \frac{1}{2}  m v²

m is the mass

v is the velocity

 Solve for K.E;

    K.E  =  \frac{1}{2}  x 0.155 x 31.4 = 2.43J

katrin2010 [14]3 years ago
3 0

Answer:

KE = ½mv² = ½(0.155)(31.4)² = 76.4 J

Explanation:

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Consider the system consisting of two pendulums coupled by a spring. Write the equations of motion in matrix form. Use small ang
Flura [38]

Answer:

hello your question is incomplete attached below is the complete question

and solution to the question

Explanation:

To write The equation of the motion in Matrix form

i)First we write the net torque equation for left mass

ii)Next we write the net torque equation for right mass

iii) represent the equation of motion in Matrix form

8 0
3 years ago
Nicole throws a ball straight up. Chad watches the ball from a window 5.0 m above the point where Nicole released it. The ball p
WARRIOR [948]

Answer:

14.14 m/s

Explanation:

As total mechanical energy is conserved, if the potential energy is the same at Chad's position no matter if the ball is travelling up or down, then its kinetic energy, and speed, is also the same too.

Therefore, the ball would have a speed of 10m/s when it's passing Chad the 1st time. Since we know that Chad is at 5m high from the release point, we can use the following equation of motion:

v^2 - v_0^2 = 2g\Delta s

where v = 10 m/s is the velocity of the ball when it passes Chad, v_0 is the initial velocity of the ball when it releases, g = 10 m/s2 is the deceleration of the can, and \Delta s = 5 m is the distance traveled between Nicole and Chad. We can solve for v0:

10^2 - v_0^2 = 2*(-10)*5

100 - v_0^2 = -100

v_0^2 = 200

v_0 = \sqrt{200} = 14.14 m/s

4 0
3 years ago
What happens to the force needed to stretch a rubber band when putting it on a stack of papers?
zmey [24]

Answer:the force is needed to stretch it farther.

Explanation: the definition of force is push or pull so imagine stretching a rubber band your pulling the band which means you increase the force.

4 0
3 years ago
Read 2 more answers
1. 412.9 g of dry ice sublimes at room temperature. a. What’s changing? --- sublimation b. What constant will you use? ----- 25.
hoa [83]

1. 236 kJ

a. The phase (or state of matter) of the substance: from solid state to gas state (sublimation)

b. The enthalphy of sublimation, given by: \lambda=571 J/g

c. The equation to use will be Q=m\lambda, where m is the mass of dry ice and \lambda is the enthalpy of sublimation

d. The energy is being absorbed, because the heat is transferred from the environment to the dry ice: as a consequence, the bonds between the molecules of dry ice break and then move faster and faster, and so the substance turns from solid into gas directly.

e. The amount of energy being transferred is

Q=m\lambda=(412.9 g)(571 J/g)=2.36\cdot 10^5 J=236 kJ

2.  165 kJ

a. The phase (or state of matter) of the substance: from gas state to liquid state (condensation)

b. The latent heat of vaporisation of water, given by \lambda=2260 J/g

c. The equation to use will be Q=m\lambda, where m is the mass of steam that condenses and \lambda is the latent heat of vaporisation

d. The energy is being released, since the substance turns from a gas state (where molecules move faster) into liquid state (where molecules move slower), so the internal energy of the substance has decreased, therefore heat has been released

e. The amount of energy being transferred is

Q=m\lambda=(72.9 g)(2260 J/g)=1.65\cdot 10^5 J=165 kJ

3. 3.64 kJ

a. Only the temperature of the substance (which is increasing)

b. The specific heat capacity of silver, which is C_s = 0.240 J/gC

c. The equation to use will be Q=m C_s \Delta T, where m is the mass of silver, Cs is the specific heat capacity and \Delta T the increase in temperature

d. The energy is being absorbed by the silver, since its temperature increases, this means that its molecules move faster so energy should be provided to the silver by the surroundings

e. The amount of energy being transferred is

Q=m C_s \Delta T=(39.2 g)(0.240 J/gC)(412.9^{\circ}C-25.9^{\circ}C)=3641=3.64 kJ

4. 89 kJ

a. Both the phase of the substance (from solid to liquid) and then the temperature

b. The latent heat of fusion of ice: \lambda=334 J/g and the specific heat capacity of water: C_s=4.186 J/gC

c. The equation to use will be Q=m\lambda + m C_s \Delta T, where m is the mass of ice, \lambda the latent heat of fusion of ice, Cs is the specific heat capacity of water and \Delta T the increase in temperature

d. The energy is being absorbed by the ice, at first to break the bonds between the molecules of ice and to cause the melting of ice, and then to increase the temperature of the water

e. The amount of energy being transferred is

Q=m\lambda +m C_s \Delta T=(156.3 g)(334 J/g)+(156.3 g)(4.186 J/gC)(56.232^{\circ}C-0^{\circ}C)=8.9\cdot 10^4 J=89 kJ

6 0
3 years ago
If the mass of an object is 200kg and the applied force is 2600N, calculate the Acceleration.​
Aliun [14]

Answer:

<em>13 m/s²</em>

Explanation:

Mass of object = 200 Kg

Applied force = 2600 N

Acceleration  = ?

Solution:

Definition:

The acceleration is rate of change of velocity of an object with respect to time.

Formula:

a = Δv/Δt

a = acceleration

Δv = change in velocity

Δt = change in time

Units:

The unit of acceleration is m.s⁻².

Acceleration can also be determine through following formula,

F = m × a

a = F/m  (N = kgm/s²)

a = 2600 kgm/s² / 200 Kg

a = 13 m/s²

6 0
3 years ago
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