air is a mixture and not a pure substance.
<span>2.56 sec (t=1/0.39)
f=3.9/10</span>
<h3>

</h3><h3>Given</h3>
v = 20m\s
a = 3m\s^2
t = 4sec
Firstly we have to find u
a = 
3m\s =
12m\s = 20 - u
20 - u = 12m\s
- u = -8
u = 8
Now we can easily find distance by using second equation of motion
s = ut + 1\2 at^2
s = 8(4) + 1\2(3)(16)
s = 32 + 24
s = 56
So distance is 56 m\s hope it helps
Answer:
Magnitude of vector A = 0.904
Explanation:
Vector A , which is directed along an x axis, that is

Vector B , which has a magnitude of 5.5 m


The sum is a third vector that is directed along the y axis, with a magnitude that is 6.0 times that of vector A 
Comparing we will get

Substituting in 

So we have

Magnitude of vector A = 0.904
Refraction is
the bending of the waves which is result of the fact that different parts of
the wave reach the water with different speeds because of the angle approaching
the shore.
<span>The
wave refraction disperses the wave energy in quiet water areas and sand is
deposited.<span> </span></span>