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e-lub [12.9K]
3 years ago
13

Which term describes the point when two objects reach the same temperature and there is no longer a transfer of energy through h

eat?
Physics
1 answer:
yaroslaw [1]3 years ago
5 0
The term you need to know is equilibrium. Technically it means that heat gained = heat lost. Normally in beginning chemistry classes the evidence for this condition is a stable temperature. 
You might be interested in
Explain the difference between SI base units and SI delivered units
castortr0y [4]

SI Units are based on meters, kilograms, seconds, amperes, kelvins, candelas, and moles, together with a set of prefixes to indicate multiplication or division by a power of ten.

There are seven SI base units, which are:

m - Meter - Length.

s - Second - Time.

mol/Mole - Amount of Substance.

A - Ampere - Electric Current.

K - Kelvin - Temperature.

cd - Candela - Luminous Intensity.

kg - Kilogram - Mass.

I think that the delivered units are how they are used such as watts which are equal to one joule per second. Others are “ergs per second (erg/s), horsepower (hp), metric horsepower (Pferdestärke (PS) or cheval vapeur (CV)), and foot-pounds per minute.”

So, SI base units are the basic units of things such as length or temperature. This would mean that the delivered units are the specific units per something like miles per hour.

3 0
4 years ago
If a diode at 300°K with a constant bias current of 100μA has a forward voltage of 700mV across it, what will the voltage drop a
MAVERICK [17]

Answer:

the voltage drop across this same diode will be 760 mV

Explanation:

Given that:

Temperature T = 300°K

current I_1 = 100 μA

current I_2 = 1 mA

forward voltage V_r = 700 mV = 0.7 V

To objective is to find the voltage drop across this same diode  if the bias current is increased to 1mA.

Using the formula:

I = I_o \begin {pmatrix}  e^{\dfrac{V_r}{nv_T}-1} \end {pmatrix}

I_1 = I_o \begin {pmatrix}  e^{\dfrac{V_r}{nv_T}-1} \end {pmatrix}

where;

V_r = 0.7

I_1 = I_o \begin {pmatrix}  e^{\dfrac{0.7}{nv_T}-1} \end {pmatrix}

I_2 = I_o \begin {pmatrix}  e^{\dfrac{V_r'}{nv_T}-1} \end {pmatrix}

\dfrac{I_1}{I_2} = \dfrac{ I_o \begin {pmatrix}  e^{\dfrac{0.7}{nv_T}-1} \end {pmatrix} }{  I_o \begin {pmatrix}  e^{\dfrac{V_r'}{nv_T}-1} \end {pmatrix} }

\dfrac{100 \ \mu A}{1 \ mA} = \dfrac{ \begin {pmatrix}  e^{\dfrac{0.7}{nv_T}-1} \end {pmatrix} }{  \begin {pmatrix}  e^{\dfrac{V_r'}{nv_T}-1} \end {pmatrix} }

Suppose n = 1

V_T = \dfrac{T}{11600} \\ \\ V_T = \dfrac{300}{11600} \\ \\ V_T = 25. 86 \ mV

Then;

e^{\dfrac{V_r'}{nv_T}-1} = 10 \begin {pmatrix}  e ^{\dfrac{ 0.7} { nV_T} -1} \end {pmatrix}

e^{\dfrac{V_r'}{nv_T}-1} = 10 \begin {pmatrix}  e ^{\dfrac{ 0.7} { 25.86} -1} \end {pmatrix}

e^{\dfrac{V_r'}{nv_T}-1} = 5.699 \times 10^{12}

{e^\dfrac{V_r'}{nv_T}} = 5.7 \times 10^{12}

{\dfrac{V_r'}{nv_T}} =log_{e ^{5.7 \times 10^{12}}}

{\dfrac{V_r'}{nv_T}} =29.37

V_r'=29.37 \times nV_T

V_r'=29.37 \times 25.86

V_r'=759.5 \ mV

Vr' \simeq 760 mV

Thus, the voltage drop across this same diode will be 760 mV

3 0
3 years ago
Name two elements that have similar properties. How can you tell using the periodic table?
tangare [24]
Helium and nitrogen because they are both from the noble gas group.
7 0
4 years ago
During a hard sneeze, your eyes might shut for 0.32 s. If you are driving a car at 76 km/h during such a sneeze, how far does th
garik1379 [7]

Answer:

Distance, d = 6.75 meters

Explanation:

Given that,

Time taken by the eyes to shut during a hard sneeze, t = 0.32 s

Speed of the car, v = 76 km/h = 21.11 m/s

We need to find the distance covered by the car during this time. The product of speed and the time taken by the car is called the distance covered by the it. Mathematically,

d=v\times t

d=21.11\times 0.32

d = 6.75 meters

So, the car will cover 6.75 meters during that time. Hence, this is the required solution.

8 0
3 years ago
The magnet below is cut in half. what will be the result?
ozzi
<h2>Answer:</h2>

C.

<h2>Explanation:</h2>

This is what we call a permanent magnet. By the  way, the magnetic phenomena were first observed about 2500 years ago near the ancient city of Magnesia, what is today Manisa, located in western Turkey, when people saw fragments of magnetized iron. So <em>what happens if you cut a magnet in half? </em>Well, a magnet has two ends, the first one is called a north pole or N pole while the  other end is a south pole or S pole, so if you break a bar magnet, each piece  has a north and south pole, no matter the size of each new bar although the smaller the  piece, the weaker its magnetism. This is true because unlike electric charges, you always find magnetic poles  in pairs, that is, ¡they can't be isolated! The option is C. because in the great bar the north pole is to the left while the south pole is to right.

3 0
3 years ago
Read 2 more answers
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