Answer:
a. an increase in the mass on the spring.
Explanation:
T = 2π/ω = 2π/√(k/m) = 2π√(m/k)
2π is a constant
as m is in the numerator, increasing mass will increase the period.
If he dropped them both at the same time, then as close as anyone could tell, they both hit the ground at the same time.
B because that’s why they are going out of the circle
Quantity of charge unloaded = 51.9 Coulombs
Potential difference = 10.93 megavolts = 1.093 x 10⁷ volts
1 volt = 1 joule per coulomb
1.093 x 10⁷ volts = 1.093 x 10⁷ joules per coulomb
Energy = (1.093 x 10⁷ J/C) x (51.9 C)
Energy = 567.267 megaJoules
That's <em>5.67 x 10⁸ Joules</em> .
==> My wife's blow-dryer is marked 1260 watts.
If the energy in this lightning strike could be collected, bottled, stored, and used as needed, it could run my wife's blow-dryer for 125 hours. That would save us more than $30 on our electric bill !
Answer:
0.73 m/s
Explanation:
From Newton second law of motion,
I = m(v-u)...................... Equation 1
Where I = Impulse, m = mass of the person, v = final velocity, u = Initial velocity.
make v the subject of the equation
v =(I/m)+u................. Equation 2
Note: u = 0 m/s as the person is falling from an height.
Given: I = 55 Ns, m = 75 kg, u = 0 m/s
Substitute into equation 2
v = 55/75
v = 0.73 m/s
