Answer:
the Molar heat of Combustion of diphenylacetylene
= 
Explanation:
Given that:
mass of diphenylacetylene
= 0.5297 g
Molar Mass of diphenylacetylene
= 178.21 g/mol
Then number of moles of diphenylacetylene
= 
= 
= 0.002972 mol
By applying the law of calorimeter;
Heat liberated by 0.002972 mole of diphenylacetylene
= Heat absorbed by
+ Heat absorbed by the calorimeter
Heat liberated by 0.002972 mole of diphenylacetylene
= msΔT + cΔT
= 1369 g × 4.184 J g⁻¹°C⁻¹ × (26.05 - 22.95)°C + 916.9 J/°C (26.05 - 22.95)°C
= 17756.48 J + 2842.39 J
= 20598.87 J
Heat liberated by 0.002972 mole of diphenylacetylene
= 20598.87 J
Heat liberated by 1 mole of diphenylacetylene
will be = 
= 6930979.139 J/mol
= 6930.98 kJ/mol
Since heat is liberated ; Then, the Molar heat of Combustion of diphenylacetylene
= 
Explanation:
Electromagnetic wave Wavelength
(1) Microwave = 1 m to 1 mm =
to 
(2) Ultraviolet = 10 nm to 400 nm
(3) Radio waves = 1 mm to 100 km =
to 
(4) Infrared = 700 nm to 1 mm
(5) X-ray = 0.01 nm to 10 nm
(6) Visible = 400 nm t0 700 nm
a) In order of increasing wavelength:
: 5 < 2 < 6 < 4 < 1 < 3
b) Frequency of the electromagnetic wave given as:

= frequency
= Wavelength
c = speed of light

So, the increasing order of frequency:
: 3 < 1 < 4 < 6 < 2 < 5
c) Energy(E) of the electromagnetic wave is given by Planck's equation :


So, the increasing order of energy:
: 3 < 1 < 4 < 6 < 2 < 5
Answer:
o
Explanation:
it is not a gas because the particles do not move freely it may be a liquid or a solid partly and mostly liquidized.
Answer: The correct answer is it emits light.
Explanation:
When an electron is present in ground level that is the lower energy level and moves to the higher energy level, the energy is provided to the electron which means that it absorbs light. This is known as absorption.
When an electron present in the higher energy level comes back to the lower energy level, it emits radiations in the form of light. This is known as emission.
Hence, the correct answer is it emits light.
where is the diagram?
without the diagram i can't help