Question

An automobile of mass 1.46 cross times to the power of blank 10 cubed kg rounds a curve of radius 25.0 m with a velocity of 15.0 m/s. The centripetal force exerted on the automobile while rounding the curve is
A. 1.31 x 10 to the power of 4 N


B. 1.43 x 10 to the power of 4 N


C. 3.14 x 10 to the power of 4 N


C. 4.10 x 10 to the power of 4 N


D. 6.08 x 10 to the power of 4N

Answer 1

The centripetal force exerted on the automobile while rounding the curve is $1.31\times10^4 N$

Explanation:

given that

$Mass\ of\ the\ automobile\ m =1.46\times 10^3 kg\\radius\ of\ the\ curve\ r =25 m\\velocity\ of\ the\ automobile\ v=15m/s$

Objects moving around a circular track will experience centripetal force towards the center of the circular track.

$centripetal\ force=mv^2/r\\=1.46\times10^3\times15^2/25\\=1.46\times 10^3\times 225/15\\=1.31\times 10^4 N$