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3 years ago

The distance between Jupiter and the Sun is 5.2 AU. What is the distance in millions of kilometers?

Physics

1 answer:

miss Akunina [59]3 years ago

8 0

Answer:

777.9 Mkm

Explanation:

(M = Mega = $10^{6}$ )

AU is the Astronomical Unit for distance (1AU=149,597,870.691 km)

The total distance in km then is:

$5.2 * 149,597,870.691 km = 777908927.593 km$

To give the result in millions, we use the prefix Mega:

$(\frac{1M}{10^{6} } ) * 777908927.593 km = 777.9 Mkm$

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3 years ago

Given Vout = 17.33 vpp and R1 = 3 kΩ, find the value of RF required to provide Av = 4.33. (Round your answer to 2 decimal places

Olenka [21]

Answer:

The magnitude of $V_{2}$ is 4 V and phase of input voltage is zero

Explanation:

Given:

Output voltage $V_{out} = 17.33$

Resistance $R_{1} = 3$ kΩ

Voltage gain $A_{v} = 4.33$

For finding feedback resistance we use gain equation

Gain equation for non inverting op-amp is given by,

$A_{v} = 1+\frac{R_{f} }{R_{1} }$

$4.33 = 1+ \frac{R_{f} }{3 k }$

$R_{f}$ ≅ 10 kΩ

For finding input voltage we use,

$A_{v} = \frac{V_{out} }{V_{2} }$

$V_{2} = \frac{17.33}{4.33}$

$V_{2} = 4$ V

The Phase of $V_{2}$ is zero because output voltage phase is 360°

Therefore, the magnitude of $V_{2}$ is 4 V and phase of input voltage is zero

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