All categories

3 years ago

The distance between Jupiter and the Sun is 5.2 AU. What is the distance in millions of kilometers?

Physics

1 answer:

miss Akunina [59]3 years ago

8 0

Answer:

777.9 Mkm

Explanation:

(M = Mega = $10^{6}$ )

AU is the Astronomical Unit for distance (1AU=149,597,870.691 km)

The total distance in km then is:

$5.2 * 149,597,870.691 km = 777908927.593 km$

To give the result in millions, we use the prefix Mega:

$(\frac{1M}{10^{6} } ) * 777908927.593 km = 777.9 Mkm$

You might be interested in

The substances referenced in the table are being considered for use in cooking materials. Since the materials must be melted dur

frutty [35]

Brass requires more energy than silver

Aluminum requires more energy than copper

Aluminum requires more energy than brass

Explanation:

The specific heat capacity of a substance indicates the amount of heat energy required to raise 1 kg of that substance by 1 degree in temperature.

Mathematically:

$C=\frac{Q}{m\Delta T}$

where

Q is the heat supplied to the substance

m is the mass of the substance

$\Delta T$ is the change in temperature

Therefore, the higher the specific heat capacity of a substance, the more energy is needed to increase its temperature.

Here we can compare the specific heat capacity of the materials mentioned:

Silver: $C=0.233 J/gK$

Brass: $C=0.380 J/gK$

Platinum: $C=0.130 J/gK$

Aluminium: $C=0.910 J/gK$

Copper: $C=0.390 J/gK$

Therefore, the correct statements are:

Brass requires more energy than silver

Aluminum requires more energy than copper

Aluminum requires more energy than brass

Learn more about specific heat:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

3 0

3 years ago

g An astronaut must journey to a distant planet, which is 189 light-years from Earth. What speed will be necessary if the astron

Butoxors [25]

Answer:

The value is $v = 2.999 *10^{8} \ m/s$

Explanation:

From the question we are told that

The time taken to travel to the planet from earth is $t = 189 \ light-years$

The time to be spent on the ship is $t_{s} = 12 \ years$

Generally speed can be obtained using the mathematical relation represented below

$t_s = 2 * t * \sqrt{1 - \frac{v^2}{c^2 } }$

The 2 in the equation show that the trip is a round trip i.e going and coming back

=> $12 = 2 * 189 * \sqrt{1 - \frac{v^2}{(3.0*10^{8})^2 } }$

=> $v = 2.999 *10^{8} \ m/s$

5 0

3 years ago

Why is the contribution of the wavelets lying on the back of secondary wave front zero?

Tresset [83]

Answer:

The contribution of the wavelets lying on the back of the wave front is zero because of something known as the Obliquity Factor. It is assumed that the amplitude of the secondary wavelets is not independent of the direction of propagation, Sources: byju's.com

3 0

2 years ago

Read 2 more answers

A balance uses small metal weights of known mass to determine the mass of a substance. Where would a balance NOT function correc

tatuchka [14]

Answer:

D is the answer.

Explanation:

Just do it.

6 0

3 years ago

Read 2 more answers

The period of a satellite circling planet Nutron is observed to be 84 s when it is in a circular orbit with a radius of 8.0 x 10

antoniya [11.8K]

Answer:

4.3 * 10^28 kg

Explanation:

Given:

Period, T = 84s

Radius of satellite orbit, r = 8*10^6

Using the relation :

M = 4π²r³ / GT²

Where G = Gravitational constant, 6.67 * 10^-11

M = 4*π^2*(8*10^6)^3 / 6.67 * 10^-11 * 84^2

M = (20218.191872 * 10^18) / 47063.52 * 10^-11

M = 0.4295937 * 10^18 - (-11)

M = 0.4295937 * 10^29

M = 4.295937 * 10^28 kg

M = 4.3 * 10^28 kg

Mass of planet Nutron = 4.3 * 10^28 kg

8 0

3 years ago