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3 years ago

The distance between Jupiter and the Sun is 5.2 AU. What is the distance in millions of kilometers?

Physics

1 answer:

miss Akunina [59]3 years ago

8 0

Answer:

777.9 Mkm

Explanation:

(M = Mega = $10^{6}$ )

AU is the Astronomical Unit for distance (1AU=149,597,870.691 km)

The total distance in km then is:

$5.2 * 149,597,870.691 km = 777908927.593 km$

To give the result in millions, we use the prefix Mega:

$(\frac{1M}{10^{6} } ) * 777908927.593 km = 777.9 Mkm$

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Answer:

Josie's ball faster than T

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1 year ago

Humans have three types of cone cells in their eyes, which are responsible for color vision. Each type absorbs a certain part of

xxMikexx [17]

Answer:

Frequency of the light will be equal to $6.97\times 10^{1}Hz$

Explanation:

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We have to find the frequency of light

We know that velocity is equal to $v=\lambda f$ , here $\lambda$ is wavelength and f is frequency of light

So frequency of light will be equal to $f=\frac{v}{\lambda }=\frac{3\times 10^8}{430\times 10^{-9}}=6.97\times 10^{1}Hz$

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2 years ago

A 12,000kg. railroad car is traveling at +2m/s when it

ivann1987 [24]

Answer:

The final velocity of the two railroad cars is 1.09 m/s

Explanation:

Since we are given that the two cars lock together it shows that the collision is inelastic in nature. The final velocity due to inelastic collision is given by

$\mathrm{V}=\frac{V 1 M 1+V 2 M 2}{M 1+M 2}$

where

V= Final velocity

M1= mass of the first object in kgs = 12000

M2= mas of the second object in kgs = 10000

V1= initial velocity of the first object in m/s = 2m/s

V2= initial velocity of the second object in m/s = 0 (given at rest)

Substituting the given values in the formula we get

V = 2×12000 + 0x100012000 + 10000= 2400022000= 1.09 m/s

$\mathrm{V}=\frac{2 \times 1200+0 \times 1000}{12000+10000}=\frac{24000}{22000}=1.09 \mathrm{m} / \mathrm{s}$

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3 years ago

When must a psychological researcher debrief human test subjects?

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Psychological researchers must debrief human test subjects at the end of every experiment.

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Debriefing a subject after a study is an essential opportunity for the researcher to explain the purpose and aim of the study to the subject, make sure the subject is not harmed or mentally disturbed, clarify why deception was used (if deception was involved) and overall, to clarify any questions or doubts the subject might have.

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2 years ago

A positive test charge of 8.5 × 10 negative 7 Columbus experiences a force of 4.1 × 10 negative 1 N calculate the electric field

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Explanation:

direction of electric field is same as that of force experienced by the test charge

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2 years ago