Answer:
upthrust or BUOYANT FORCE =Vdg
volume=LWH
upthrust=(4cm×5cm×2cm)×1g/cm²×g
upthrust=40cm³×1g/cm³×g
upthrust=40gf or 0.04kg×10m/s²=0.4N
weight of the displaced liquid is upthrust.
so mass=40g or 0.04kg
upthrust=40gf or 0.4Nand mass of the displaced liquid=40g or 0.04kg
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Answer: B (on the rough side)
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Answer:
none
Explanation:
Newton's first law says an object in motion will stay in motion at the same speed and direction unless acted upon by some force.
No force is necessary for the object to keep its speed and direction on a frictionless surface.
*Graph is attached with the answer*
Answer:
Total distance traveled by the car is 40 m
Explanation:
It can be seen from the graph that for the first 4 second car is moving with uniform acceleration and for next 2 second it has constant velocity
So, we solved this question in 2 parts
Part 1:
initial velocity = v₁ = 0 m/s
final velocity = v₂ = 10 m/s
time = t = 4 s
acceleration = a = (v₂ - v₁)/t
a = 10/4 = 2.5 m/s²
Using 3rd equation of motion
2as = v₂² - v₁²
2(2.5)s = 10²
s₁ = 100/5
s₁ = 20 m
Part 2:
s₂ = v₂t
s₂ = 10 × 2
s₂ = 20 m
Total distance = S = s₁ + s₂
= 20 + 20
S = 40 m