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Mamont248 [21]
3 years ago
11

How much current is in a circult that includes a 9.0-volt battery and a bulb with a resistance of 4.0 ohms?

Physics
1 answer:
SVETLANKA909090 [29]3 years ago
6 0

Answer:

Current, I = 2.3 A

Explanation:

We have,

Voltage of the battery in a circuit is 9 volts

Resistance of the circuit is 4 ohms

It is required to find the current in a circuit. When the voltage and the resistance of the circuit is given then we can find the current in it is given by Ohm's law as :

V=IR

I is electric current

I=\dfrac{V}{R}\\\\I=\dfrac{9}{4}\\\\I=2.25\ A

or

I = 2.3 A

So, the current in the circuit is 2.3 A.

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Cual es la rapidez media de un guepardo que recorre 100 metros en 4 segundos? ¿Y si recorre 50 m en 2 s?
Maru [420]

Answer:

La rapidez media es 25 m/s en ambos casos.

Explanation:

Podemos definir como rapidez media al cociente entre la distancia total recorrida y el tiempo que se tardó en recorrer dicha distancia.

Así tenemos:

Rapidez media = Distancia/tiempo.

Entonces si el guepardo recorre 100m en 4 segundos, su rapidez media es:

Rapidez media = 100m/4s = 25 m/s

En el caso de que el guepardo recorre 50 metros en 2 segundos, su rapidez media será:

rapidez media = 50m/2s = 25m/s

Es el mismo resultado, pues recorrió la mitad de distancia en la mitad de tiempo.

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3 years ago
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Andrej [43]
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3 years ago
A simple pendulum consisting of a small object of mass m attached to a string of length l has a period T.
andrew-mc [135]

Answer:

Check Explanation.

Explanation:

For a simple pendulum, the period is given as

T = 2π√(L/g)

It is also given as

T = 2π√(m/k)

where

T = period of oscillation

m = mass of the pendulum

L = length

g = acceleration due to gravity

k = force constant

Equating this two equations,

2π√(L/g) = 2π√(m/k)

(L/g) = (m/k)

(m/L) = (k/g)

So, any pendulum that will have the same period as our pendulum with mass, m, and length, L, must have the ratio of (L/g) to be the same as the pendulum under consideration and the ratio of its mass to force constant (m/k) must also be equal to this ratio.

Hope this Helps!!!

4 0
3 years ago
Show that the equilibrium temperature of the surface of the moon is 273 K assuming it has an albedo of 0.08.
const2013 [10]

Answer:

The equilibrium temperature of the surface of the moon can be found by the formula as follows:

T=(\frac{K_s(1-alebdo)}{4 \sigma})^{\frac{1}{4}}

Where K_s = 1366 W/m^2 is the solar constant and \sigma = 5.67 \times 10^ {-8}W/m^2K^{-4} is the Stefan's Boltzmann constant.

T=(\frac{1366(1-0.08)}{4\times 5.67 \times 10^ {-8}})^{\frac{1}{4}} = (55.41\times 10^8)^{\frac{1}{4}} = 272.7 K=273 K

Thus, the equilibrium temperature of the surface of the moon is 273 K.

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