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Dmitriy789 [7]
3 years ago
11

Why is the unit of velocity called derived unit ?​

Physics
1 answer:
navik [9.2K]3 years ago
6 0

Answer:

Explanation:

The general consensus is that it's more “natural” to define distance (meter) and time (second) and as base units, and derive velocity a the ratio between them. ... The general consensus is that it's more “natural” to define distance (meter) and time (second) and as base units, and derive velocity a the ratio between them.

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Write an expression for the magnitude of charge moved, Q, in terms of N and the fundamental charge e
NeTakaya

We have that for the Question "Write an expression for the <em>magnitude </em>of charge moved, Q, in terms of N and the fundamental charge e" it can be said its equation is

Q=\frac{E}{Nr^2}

       

From the question we are told

Write an expression for the <em>magnitude </em>of charge moved, Q, in terms of N and the fundamental charge e

<h3>An Expression for the <em>magnitude </em>of charge moved</h3>

Generally the equation for the  <em>magnitude </em>of charge moved, Q   is mathematically given as

Q=\frac{E}{Nr^2}

Therefore

An expression for the <em>magnitude </em>of charge moved, Q, in terms of N and the fundamental charge e" it can be

 Q=\frac{E}{Nr^2}

 

For more information on this visit

brainly.com/question/16517842

3 0
2 years ago
A copper wire has a radius of 3.5 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends o
denpristay [2]

Answer:

The tensile stress on the wire is 550 MPa.

Explanation:

Given;

Radius of copper wire, R = 3.5 mm

extension of the copper wire, e =  5.0×10⁻³ L

L is the original length of the copper wire,

Young's modulus for copper, Y =  11×10¹⁰Pa.

Young's modulus, Y is given as the ratio of tensile stress to tensile strain, measured in the same unit as Young's modulus.

Y =\frac{Tensile \ stress}{Tensile \ strain} \\\\Tensile \ stress = Y*Tensile \ strain\\\\But, Tensile \ strain = \frac{extension}{original \ Length} = \frac{5.0*10^{-3} L}{L} = 5.0*10^{-3}\\\\Tensile \ stress = 11*10^{10} *5.0*10^{-3} \ = 550*10^6 \ Pa

Therefore, the tensile stress on the wire is 550 MPa.

8 0
3 years ago
How much power does it take to lift 30.0 N 10.0 m high in 5.00 s?
Rudik [331]

Power = work/time = (Force times distance)/time

= (30N *10.0m)/5.00s = 300/5 = 60 Watts

7 0
4 years ago
Read 2 more answers
A coil has N turns enclosing an area of A. In a physics laboratory experiment, the coil is rotated during the time interval delt
zmey [24]

Answer:

a) Magnetic flux before the plane is rotated = (BA) Wb

b) Magnetic flux after the plane is rotated = 0 Wb

c) Magnitude of the average induced emf =

(NBA)/Δt

Explanation:

The magnetic flux is given as

Φ = BA cos θ

where B = magnetic field strength

A = Cross sectional Area of the loop enclosed

θ = the angle in the equation above is between the line normal to plane (NOT the plane itself!) and the magnetic field.

a) Given that the position of the plane of each turn is perpendicular to Earth's magnetic field before being rotated.

Before the plane is rotated, θ = 0°

Φ = BA cos θ = BA cos 0° = BA

b) Given that the position of the plane of each turn is parallel to Earth's magnetic field after being rotated.

After the plane is rotated, θ = 90°

Φ = BA cos θ = BA cos 90° = 0

c) According to the Faraday's law of electromagnetic induction,

E = - N (ΔΦ/Δt) (minus sign to indicate that the direction of the induced emf is opposite the direction of the change of magnetic flux)

ΔΦ = (final Φ) - (initial Φ) = (0 - BA) = - BA

E = - N (- BA)/Δt

E = (NBA)/Δt

Hope this Helps!!!

8 0
3 years ago
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Lauren rode the bus home from the mall on Saturday. She felt the bus accelerate as it left the parking lot, and then the bus tur
Alex_Xolod [135]
A. is the one it did not say
7 0
3 years ago
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