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GarryVolchara [31]
2 years ago
10

In the diagram of a transverse wave shown, what does P represent?

Chemistry
2 answers:
Effectus [21]2 years ago
8 0
L is amplitude M is wavelength and P is frequency
damaskus [11]2 years ago
5 0

Answer:The answer is B

Explanation: I got it right on the test

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Can anyone answer this? I'd appreciate it. :0
Ganezh [65]

Answer:

Triclinic crystal forms. Also known as the rhombohedron system, its shape is three dimensional like a cube, but it has been skewed or inclined to one side making it oblique. All crystal faces are parallel to each other. A rhombohedral crystal has six faces, 12 edges, and 8 vertices.

bascially short answer is 6 faces

8 0
3 years ago
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. Calculate the final Celsius temperature of sulfur dioxide gas if 50.0 mL of the gas at 20 C and 0.450 atm is heated until the
Anna [14]

Answer:

The final temperature of sulfur dioxide gas is 215.43 C

Explanation:

Gay Lussac's Law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that if the temperature increases the pressure increases, while if the temperature decreases the pressure decreases. In other words, the pressure and temperature are directly proportional quantities.

Mathematically, the Gay-Lussac law states that, when a gas undergoes a transformation at constant volume, the quotient of the pressure exerted by the temperature of the gas remains constant:

\frac{P}{T}=k

Assuming you have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment, by varying the temperature to a new value T2, then the pressure will change to P2, and it will be true:

\frac{P1}{T1} =\frac{P2}{T2}

The reference temperature is the absolute temperature (in degrees Kelvin)

In this case:

  • P1= 0.450 atm
  • T1= 20 C= 293.15 K (being 0 C= 273.15 K)
  • P2=0.750 atm
  • T2= ?

Replacing:

\frac{0.450atm}{293.15 K} =\frac{0.750 atm}{T2}

Solving:

T2 =\frac{0.750 atm}{\frac{0.450atm}{293.15 K} }

T2=\frac{0.750 atm}{0.450 atm} *293.15K

T2=488.58 K

Being 273.15 K= 0 C, then 488.58 K= 215.43 C

<u><em>The final temperature of sulfur dioxide gas is 215.43 C</em></u>

6 0
3 years ago
Why is desertification a problem?
Gnesinka [82]
Because if all the trees and grasslands are to disappear and turn into deserts then there would be no oxygen for us
6 0
3 years ago
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Explain how venus rotation is different from earths
saul85 [17]
It has the slowest rotation of all planets. 

like 240 earth days...in retrograde clockwise turns
7 0
3 years ago
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A certain liquid X has a normal boiling point of 111.20 celsius and a boiling point elevation constant Kb=0.95. calculate the bo
Goshia [24]

Answer: the boiling point is = 137.325°C

Explanation:

From the formula: ∆Tb= Kb*m

From the question, Kb= 0.95, m= 27.5, T1= 111.2°C

Substitute into ∆Tb= Kb*m

∆Tb= 0.95*27.5= 26.125

∆Tb= T2-T1

Hence

T2- 111.2=26.125

T2= 26.125+ 111.2= 137.325°C

8 0
3 years ago
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