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Thepotemich [5.8K]
3 years ago
14

Write a balanced chemical equation for the reaction between ammonium

Chemistry
1 answer:
Natasha2012 [34]3 years ago
4 0

Answer:

 (NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→  AlPO₄(l) + 3NH₄NO₃(l)

Explanation:

Data Give:

Reaction between ammonium phosphate solution and solution of aluminum nitrate

  • Write a balanced chemical equation
  • include phase symbols

Details:

To write a balanced chemical equation we have to know formula units of compounds or molecules

Formula units

ammonium phosphate : (NH₄)₃PO₄

aluminum nitrate: Al(NO₃)₃

ammonium nitrate: NH₄NO₃

Now to write a chemical equation

  • we have to write the chemical formulas  or formula unit of each compound
  • write the reactant on left side of the arrow
  • write the product on the right side of the arrow
  • put a plus sign in 2 reactants and products on each side of the arrow
  • balance the equation by putting coefficient with compound formula
  • write the phase symbols on the right corner of the compound formula in brackets

So the Reaction will be

                      (NH₄)₃PO₄ + Al(NO₃)₃ -----------→  AlPO₄ + NH₄NO₃

Now balance the Chemical equation

                     (NH₄)₃PO₄ + Al(NO₃)₃ -----------→  AlPO₄ + 3NH₄NO₃

Now write the phase Symbols

                     (NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→  AlPO₄(l) + 3NH₄NO₃(l)

all compounds in the reaction are in liquid form and soluble in water

*** Note:

There is no aluminum nitrite in chemicals formulas

Also ammonium nitrite can not be used in pure isolated form due to its highly instability

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The normal freezing point of water (H2O) is 0.00 oC and its Kf value is 1.86 oC/m. A nonvolatile, nonelectrolyte that dissolves
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Answer:

3.74g of ethylene glycol must be added to decrease the freezing point by 0.400°C

Explanation:

One colligative property is the freezing point depression due the addition of a solute. The equation is:

ΔT=Kf*m*i

<em>Where ΔT is change in temperature = 0.400°C</em>

<em>Kf is freezing point constant of the solvent = 1.86°C/m</em>

<em>m is molality of the solution (Moles of solute / kg of solvent)</em>

<em>And i is Van't Hoff constant (1 for a nonelectrolyte)</em>

Replacing:

0.400°C =1.86°C/m*m*1

0.400°C / 1.86°C/m*1 = 0.215m

As mass of solvent is 280.0g = 0.2800kg, the moles of the solute are:

0.2800kg * (0.215moles / 1kg) = 0.0602 moles of solute must be added.

The mass of ethylene glycol must be added is:

0.0602 moles * (62.10g / mol) =

3.74g of ethylene glycol must be added to decrease the freezing point by 0.400°C

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