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Thepotemich [5.8K]
3 years ago
14

Write a balanced chemical equation for the reaction between ammonium

Chemistry
1 answer:
Natasha2012 [34]3 years ago
4 0

Answer:

 (NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→  AlPO₄(l) + 3NH₄NO₃(l)

Explanation:

Data Give:

Reaction between ammonium phosphate solution and solution of aluminum nitrate

  • Write a balanced chemical equation
  • include phase symbols

Details:

To write a balanced chemical equation we have to know formula units of compounds or molecules

Formula units

ammonium phosphate : (NH₄)₃PO₄

aluminum nitrate: Al(NO₃)₃

ammonium nitrate: NH₄NO₃

Now to write a chemical equation

  • we have to write the chemical formulas  or formula unit of each compound
  • write the reactant on left side of the arrow
  • write the product on the right side of the arrow
  • put a plus sign in 2 reactants and products on each side of the arrow
  • balance the equation by putting coefficient with compound formula
  • write the phase symbols on the right corner of the compound formula in brackets

So the Reaction will be

                      (NH₄)₃PO₄ + Al(NO₃)₃ -----------→  AlPO₄ + NH₄NO₃

Now balance the Chemical equation

                     (NH₄)₃PO₄ + Al(NO₃)₃ -----------→  AlPO₄ + 3NH₄NO₃

Now write the phase Symbols

                     (NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→  AlPO₄(l) + 3NH₄NO₃(l)

all compounds in the reaction are in liquid form and soluble in water

*** Note:

There is no aluminum nitrite in chemicals formulas

Also ammonium nitrite can not be used in pure isolated form due to its highly instability

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Explanation:

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Is water going from liquid to solid a physical or chemical change and why
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What volume of water has the same mass as 9.0m3 of ethyl alcohol?
Triss [41]
This question requires the knowledge of density. 

The density of ethyl alcohol = 789 kg m⁻³
The density of water = 1000 kg m⁻³

Density = Mass / Volume 

By applying ethyl alcohol,
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hence the mass of 0.9 m³ ethyl alcohol is 710.1 kg.

Then by applying water,
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8 0
3 years ago
Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.
Colt1911 [192]

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\%C_E = \frac{E}{T} * 100\%

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In (Ca(OH)_2)

The amount of all elements is: (i.e formula mass of (Ca(OH)_2))

T = 1 * Ca + 2 * H + 2 * O

T = 1 * 40 + 2 * 1 + 2 * 16

T = 74

The amount of calcium is: (i.e formula mass of calcium)

E = 1 * Ca

E = 1 * 40

E = 40

So, the percentage component of calcium is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{40}{74} * 100\%

\%C_E = \frac{4000}{74}\%

\%C_E = 54.05\%

The amount of hydrogen is:

E = 2 * H

E = 2 * 1

E = 2

So, the percentage component of hydrogen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{2}{74} * 100\%

\%C_E = \frac{200}{74}\%

\%C_E = 2.70\%

Similarly, for oxygen:

The amount of oxygen is:

E = 2 * O

E = 2 * 16

E = 32

So, the percentage component of oxygen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{32}{74} * 100\%

\%C_E = \frac{3200}{74}\%

\%C_E = 43.24\%

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Answer:

um pretty sure this is it

Explanation:

The fission process also releases extra neutrons, which can then split additional atoms, resulting in a chain reaction that releases a lot of energy.

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