Option C: Sulfur Dioxide is the answer
Hope this helps
Answer:
a)4.40 x 10^-3 M/s
b) 8.80 x 10^-3 M/s
Explanation:
Given the reaction equation;
H2O2 (aq) + 3I- (aq) + 2H+ --------> I3- (aq) + 2H2O (l)
We can now write;
a) Rate = -Δ[I-]/3Δt
- (0.868 M - 1.000 M)/ 3 (10.0 s - 0 s)
= 4.40 x 10^-3 M/s
Similarly;
b) Rate = -Δ[H+]/2Δt
- (0.868 M - 1.000 M)/ 3 (10.0 s - 0 s)
(4.40 x 10^-3 m/s) x 2
= 8.80 x 10^-3 M/s
I believe that the best answer among the choices provided by the question is the third choice , a change in number
Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.
Answer:
If 700 g of water at 90 °C loses 27 kJ of heat, its final temperature is 106.125 °C
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
In this way, between heat and temperature there is a direct proportional relationship (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also increases; and the same happens when either of the two decreases .). The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:
Q = c * m * ΔT
Where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature, ΔT= Tfinal - Tinitial
In this case:
- Q= 27 kJ= 27,000 J (being 1 kJ=1,000 J)
- m=700 g
- ΔT= Tfinal - Tinitial= Tfinal - 90 °C
Replacing:
Solving:
16.125 °C= Tfinal - 90 °C
Tfinal= 16.125 °C + 90 °C
Tfinal= 106.125 °C
<u><em>If 700 g of water at 90 °C loses 27 kJ of heat, its final temperature is 106.125 °C</em></u>
Answer:
<h2>
Continue to move at 30 mph</h2>
Explanation:
Newton's first law of motion :
"Every object persists in its state of rest or uniform motion in a straight line unless it is compelled to change that state by forces exerted on it."
From the question we know that the net forces on the object were zero or that the there were no unbalanced forces on it.
Therefore we can assume that the object is moving along a straight line.
And the object was moving at a constant speed of 30 mph.
So it is clear from the Newton's first law that the object will remain in the state of motion as it was earlier.
That is the object will remain in motion at constant speed of 30 mph.