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3 years ago

Which of the following steps correctly 1.25 of fluorine to an equivalent mass of fluorine in grams?

Chemistry

1 answer:

inessss [21]3 years ago

8 0

<h3>Answer:</h3>

D. Multiply the atomic mass of fluorine by 1.25

<h3>Explanation:</h3>

<u>We are given;</u>

1.25 moles of Fluorine

We need to identify the formula that shows the equivalent in mass

We need to know the relationship between mass of an element, its atomic mass and the number of moles;

That is; Number of moles = Mass of the element ÷ Atomic mass

Therefore;

Mass of the element = Number of moles × atomic mass

Thus, in this case, to get mass we will multiply number of moles by atomic mass of Fluorine.

That is, multiply atomic mass of fluorine by 1.25 moles .

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When the equation Fe +Cl2 FeCl3 → is balanced, what isthe coefficient for Cl2?

mixas84 [53]

Answer: Option (c) is the correct answer.

Explanation:

The given reaction is as follows.

$Fe + Cl_{2} \rightarrow FeCl_{3}$

Number of atoms on reactant side are as follows.

Fe = 1
Cl = 2

Number of atoms on product side are as follows.

Fe = 1
Cl = 3

To balance the given equation, we multiply Fe by 2 and $Cl_{2}$ by 3 on the reactant side. Therefore, the balanced chemical equation will be as follows.

$2Fe + 3Cl_{2} \rightarrow FeCl_{3}$

Thus, the coefficient of $Cl_{2}$ is 3.

7 0

4 years ago

Read 2 more answers

For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell

frutty [35]

Answer:

$\large\boxed{\text{0.512 V}}$

Explanation:

We must use the Nernst equation

$E = E^{\circ} - \dfrac{RT}{zF}lnQ$

The equation for the cell reaction is is

2Cl⁻(0.384 mol·L⁻¹) + 2Co³⁺(0.324 mol·L⁻¹) ⇌ Cl₂(5.80 atm) + 2Co²⁺(0.158 mol/L)

Data:

E° = 0.483 V

R = 8.314 J·K⁻¹mol⁻¹

T = 25 °C

n = 2

F = 96 485 C/mol

Calculation:

T = 25 + 273.15 = 298.15 K

$Q = \dfrac{\text{[Cl}^{-}]^{2}[\text{Co}^{3+}]^{2}}{p_{\text{Cl}_{2}}^{2}\text{[Co}^{3+}]^{2}} = \dfrac{0.384^{2} \times 0.324^{2}}{5.80 \times 0.158^{2}} =0.1069\\\\E = 0.483 - \left (\dfrac{8.314 \times 298.15 }{2 \times 96485}\right ) \ln(0.1069)\\\\=0.483 -0.01285 \times (-2.236) = 0.483 + 0.02872 = \textbf{0.512 V}\\\text{The cell potential is } \large\boxed{\textbf{0.512 V}}$

7 0

4 years ago

What is the correct electron configuration for an element with 5 electrons in

Harlamova29_29 [7]

Answer:

it is c

Explanation:

5 0

3 years ago

A glucose solution is administered intravenously into the bloodstream at a constant rate r. As the glucose is added, it is conve

Helen [10]

Answer:

$C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}$

Explanation:

The differential equation is given as:

$\frac{dC}{dt} = r- kC$

$\frac{dC}{r- kC} = dt$

Taking integral of both sides; we have:

$\int\limits \frac{dC}{r- kC} = \int\limits dt$

$-\frac{1}{k} In(r-kC) = t+D\\In(r-kC)=-kt-kD$

$r-kC=e^{-kt-kD}$

$r-kC=e^{-kt}e^{-kD}$

$r-kC=Ae^{-kt}$

$kC=r-Ae^{-kt}$

$C=\frac{r}{k}-\frac{A}{k}e^{-kt}$

$C(t)=\frac{r}{k}-\frac{A}{k}e^{-kt}$ ------- equation (1)

If C(0)= $C_o$ ; we have:

C(0)= $\frac{r}{k}-\frac{A}{k}e^0$ (where; A is an integration constant)

$C_o = \frac{r}{k}- \frac{A}{k}$

$C_o=\frac{r-A}{k}$

$kC_o=r-A$

$A=r-kC_o$

Substituting $A=r-kC_o$ into equation (1); we have;

$C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}$

3 0

3 years ago

Cholorine is more reactive than nitrogen? why<br>

SSSSS [86.1K]

Answer:

Because of the presence of lone pairs in nitrogen it further adds to its reactivity. Hence nitrogen is more electronegative than chlorine. ... Chlorine is less reactive than nitrogen in other words nitrogen is more reactive than chlorine

Explanation:

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6 0

3 years ago