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Sonbull [250]
3 years ago
9

Which particles in atom could demonstrate that opposite charges attract

Chemistry
1 answer:
NeTakaya3 years ago
7 0

<em><u>the answer is electrons </u></em>

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Se sabe que 10 g de calcio reaccionan con 4 g de oxígeno para obtener 14 g de óxido de calcio. Indica la cantidad de óxido de ca
egoroff_w [7]

Answer:

Si se usan 50 gramos de calcio y óxigeno, se obtienen 70 gramos de óxido de calcio.

Explanation:

Hola,

En este caso, la reacción llevada a cabo es:

2Ca+O_2\rightarrow 2CaO

De este modo si asumimos el ejemplo dado, 50 gramos de calcio, cuya masa atómica es 40 g/mol y 50 g de oxígeno, cuya masa atómica como gas diatómico es 32 g/mol, antes de calcular los gramos de óxido de calcio producidos, debemos identificar el reactivo límite. Así, calculamos las moles de calcio disponibles en 50 g:

mol_{Ca}^{disponible}=50gCa*\frac{1molCa}{40gCa} =1.25molCa

Y también las moles de calcio consumidas por los 50 g de oxígeno, utilizando su relación molar 2:1:

mol_{Ca}^{consumidas\ por\ O_2}=50gO_2*\frac{1molO_2}{32gO_2} *\frac{2molCa}{1molO_2} =3.125molCa

Por lo tanto, hay menos calcio disponible que el que consume el oxígeno, por lo que el calcio esel reactivo límite. Ahora, con este, calculamos los gramos de óxido de calcio, cuya masa molar es 56 g/mol, que se producen:

m_{CaO}=1.25molCa*\frac{2molCaO}{2molCa}* \frac{56gCaO}{1molCaO}\\ \\m_{CaO}=70gCaO

Esto quiere decir que de 50 gramos de oxígeno, solo 20 gramos reaccionan para formar 70 gramos de óxido de calcio.

Saludos!

4 0
3 years ago
Read 2 more answers
Answer to A please! ASAP
Tanya [424]
The answer is electron
5 0
3 years ago
What is the specific heat of copper when heated to 221.32
Dafna1 [17]

Answer:

The specific heat of copper when heated to 221.32 (not listed form of heat measurement) is 221.32 (not listed form of heat measurement).

Explanation:

uh not really sure what else there is here, I may be missing something

5 0
3 years ago
How many atoms are in 123 g of calcium
Keith_Richards [23]

Answer:

Molar mass of Ca = 40 g / mol , given 123 g Ca is 123/40= 3.075 moles,

1 mole = 6.022 * 10^23 atoms, so 3.075 moles Ca= 18.51*10^23 atoms

Explanation:

5 0
3 years ago
Write the formula for diphosphorous pentoxide
ehidna [41]

Answer:

P4O10

Explanation:

7 0
3 years ago
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