Answer:
b. aluminum
Explanation:
The specific heat capacity is defined as the amount of heat required to raise the temperature of 1g of a material in 1°C.
Thus, the sample with the higher specific heat capacity is the sample that will require more energy to increase its temperature in 1°C, suffering the smallest change in temperature.
Thus, is the aluminium with 0.900J/gK the element that is most likely to undergo the smallest change in temperature:
<h3>b. aluminum
</h3>
Answer:
I think u mean molar mass of ca(Mno4)2
if so it is 277.949 g/ mol
Answer:
The change in entropy in the system is -231.5 J/K
Explanation:
Step 1: Data given
The normal boiling point of ethanol (C2H5OH) is 78.3 °C = 351.45 K
The molar enthalpy of vaporization of ethanol is 38.56 kJ/mol = 38560 J/mol
Mass of ethanol = 97.2 grams
Pressure = 1 atm
Step 2: Calculate the entropy change of vaporization
The entropy change of vaporization = molar enthalpy of vaporization of ethanol / temperature
The entropy change of vaporization = 38560 J/mol / 351.45 K
The entropy change of vaporization = -109.72 J/k*mol
Step 3: Calculate moles of ethanol
Moles ethanol = mass / molar mass ethanol
Moles ethanol = 97.2 grams / 46.07 g/mol
Moles ethanol = 2.11 moles
Step 4: Calculate change in entropy
For 1 mol = -109.72 J/K*mol
For 2.11 moles = -231.5 J/K
The change in entropy in the system is -231.5 J/K
Answer:
We'll have 8.0 moles Fe3O4 and 4.0 moles CO2
Explanation:
Step 1: data given
Number of moles Fe2O3 = 12.0 moles
Number of moles CO = 12.0 moles
Step 2: The balanced equation
3Fe2O3 +CO → 2Fe3O4 + CO2
Step 3: Calculate the limiting reactant
For 3 moles Fe2O3 we need 1 mol CO to produce 2 moles Fe3O4 and 1 mol CO2
Fe2O3 is the limiting reactant. It will completely be consumed (12.0 moles).
CO is in excess. There will react 12.0 / 3 = 4.0 moles
There will remain 12.0 - 4.0 = 8.0 moles
Step 4: Calculate moles products
For 3 moles Fe2O3 we need 1 mol CO to produce 2 moles Fe3O4 and 1 mol CO2
For 12.0 moles Fe2O3 we'll have 2/3 * 12.0 = 8.0 moles Fe3O4
For 12.0 moles Fe2O3 we'll have 12.0 / 3 = 4.0 moles CO2
We'll have 8.0 moles Fe3O4 and 4.0 moles CO2
