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2 years ago

Explain how the principal of uniformitarianism is used to interpret earths past

Chemistry

1 answer:

vesna_86 [32]2 years ago

3 0

Answer:

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A 4.215 g sample of a compound containing only carbon, hydrogen, and oxygen is burned in an excess of oxygen gas, producing 9.58

Scilla [17]

Answer:

$\% O=27.6\%$

Explanation:

Hello,

In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:

- Moles of carbon are contained in the 9.582 grams of carbon dioxide:

$n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2} =0.218molC$

- Moles of hydrogen are contained in the 3.922 grams of water:

$n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH$

- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:

$m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO$

Finally, we compute the percent by mass of oxygen:

$\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%$

Regards.

5 0

3 years ago

What are the solutions to the quadratic equation 2x2 + 10x - 48 = 0?<br>

Natali [406]

Answer:

Explanation:

$2x^2+10x-48\\=2\left(x^2+5x-24\right)\\x^2+5x-24\\=\left(x^2-3x\right)+\left(8x-24\right)\\=x\left(x-3\right)+8\left(x-3\right)\\=\left(x-3\right)\left(x+8\right)\\=2\left(x-3\right)\left(x+8\right)\\2\left(x-3\right)\left(x+8\right)=0\\x-3=0\\x = 0+3\\x = 3\\x+8=0\\x+8-8=0-8\\x=-8\\x=3,\:x=-8$

8 0

3 years ago

What best describes a solution ?

topjm [15]

A solution is the answer to a problem

8 0

3 years ago

Read 2 more answers

A sulfuric acid solution containing 571.3 g of h2so4 per liter of aqueous solution has a density of 1.329 g/cm3. Part a calculat

loris [4]

Mass percentage of a solution is the amount of solute present in 100 g of the solution.

Given data:

Mass of solute H2SO4 = 571.3 g

Volume of the solution = 1 lit = 1000 ml

Density of solution = 1.329 g/cm3 = 1.329 g/ml

Calculations:

Mass of the given volume of solution = 1.329 g * 1000 ml/1 ml = 1329 g

Therefore we have:

571.3 g of H2SO4 in 1329 g of the solution

Hence, the amount of H2SO4 in 100 g of solution= 571.3 *100/1329 = 42.987

Mass percentage of H2SO4 (%w/w) is 42.99 %

3 0

3 years ago

grandma baked cookies. she gave 7 to sandy. she gave half of what were left, plus one to sue. she gave 3 to stan. then she gave

scoray [572]

I believe your answer is 23.
Credit: answers.yahoo.com

Hope this helps!

8 0

3 years ago