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WITCHER [35]
3 years ago
7

Explain how the principal of uniformitarianism is used to interpret earths past

Chemistry
1 answer:
vesna_86 [32]3 years ago
3 0

Answer:

ghysdjoraiwiiwiwieidhdhdhdhd

sjjsjsndjdjd

djsi

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What is the PH of a 1.3×(10)^-9 M HBr solution?
olga nikolaevna [1]

pH solution = 8.89

<h3>Further explanation</h3>

Given

The concentration of HBr solution = 1.3 x 10⁻⁹ M

Required

the pH

Solution

HBr = strong acid

General formula for strong acid :

[H⁺]= a . M

a = amount of H⁺

M = molarity of solution

HBr⇒H⁺ + Br⁻⇒ amount of H⁺ = 1 so a=1

Input the value :

[H⁺] = 1 x  1.3 x 10⁻⁹

[H⁺] = 1.3 x 10⁻⁹

pH = - log [H⁺]

pH = 9 - log 1.3

pH = 8.89

7 0
3 years ago
Calculate with the correct number of significant figures 2.0 x 10^5 x 3.00 x 10^8
xxMikexx [17]

Answer:

the correct answer is 17 significant figures

3 0
3 years ago
Give an example of erosion.
nasty-shy [4]
Rivers/streams are eroded and can be eroded 

5 0
4 years ago
This image shows a...​
likoan [24]

Answer:

I think is the last one!!!! punnet square ⬜

5 0
3 years ago
A 0.1375-g sample of solid magnesium is burned in a constant-volume bomb calorimeter that has a heat capacity of 3024 J/°C. The
Anna35 [415]

Answer:

-24.76 kJ/g; -601.8 kJ/mol

Explanation:

There are two heat flows in this experiment.

Heat from reaction + heat absorbed by calorimeter = 0

             q1                +                     q2                         = 0

           mΔH             +                    CΔT                        = 0

Data:

m = 0.1375 g

C = 3024 J/°C

ΔT = 1.126 °C

Calculations:

0.1375ΔH + 3024 × 1.126 = 0

           0.1375ΔH + 3405 = 0

                        0.1375ΔH = -3405

                                   ΔH = -24 760 J/g = -24.76 kJ/g

ΔH = -24.76 kJ/g ×24.30 g/mol = -601.8 kJ/mol

3 0
3 years ago
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