Someone help me with this please

Which subatomic particle helps identify an elements identify

Sindrei [870]

Answer:

Protons

Explanation:

Protons are the subatomic particle that determines the identity of an element.

8 0

3 years ago

Hydrogen fluoride is used in the manufacture of Freons (which destroy ozone in the stratosphere) and in the production of alumin

Lerok [7]

Answer: The percentage yield of HF is 73.36 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For calcium fluoride:

Given mass of calcium fluoride = 6.25 kg = 6250 g (Conversion factor: 1 kg = 1000 g)

Molar mass of calcium fluoride = 78.07 g/mol

Putting values in above equation, we get:

$\text{Moles of calcium fluoride}=\frac{6250g}{78.07g/mol}=80.05mol$

For the given chemical reaction:

$CaF_2+H_2SO_4\rightarrow CaSO_4+2HF$

By Stoichiometry of the reaction:

1 mole of calcium fluoride produces 2 moles of hydrofluoric acid

So, 80.05 moles of calcium fluoride will produce = $\frac{2}{1}\times 80.05=160.1mol$ of hydrofluoric acid

Now, calculating the theoretical yield of hydrofluoric acid using equation 1, we get:

Moles of of hydrofluoric acid = 160.1 moles

Molar mass of hydrofluoric acid = 20.01 g/mol

Putting values in equation 1, we get:

$160.1mol=\frac{\text{Theoretical yield of hydrofluoric acid}}{20.01g/mol}=3203.6g=3.20kg$

To calculate the percentage yield of hydrofluoric acid, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of hydrofluoric acid = 2.35 kg

Theoretical yield of hydrofluoric acid = 3.20 kg

Putting values in above equation, we get:

$\%\text{ yield of hydrofluoric acid}=\frac{2.35g}{3.20g}\times 100\\\\\% \text{yield of hydrofluoric acid}=73.36\%$

Hence, the percentage yield of HF is 73.36 %

4 0

2 years ago

Metallic copper is formed when aluminum reacts with copper(II) sulfate according to the

katovenus [111]

Answer: Given the equation for reaction is

2 A l +C u S O 4 → A l 2 ( S O 4 ) 3 + 3 C u .

Explanation:

3 0

2 years ago

When an exothermic reaction occurs in a water solution, the temperature of the solution

iVinArrow [24]

Answer:

is hot

Explanation:

6 0

3 years ago

Read 2 more answers

The solubility of a gas is 0.890 g/L at a pressure of 120 kPa. What is the solubility of the gas if the pressure is changed to 1

IgorC [24]

The solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

<h3>Effect of Pressure on Solubility </h3>

As the pressure of a gas increases, the solubility increases, and as the pressure of a gas decreases, the solubility decreases.

Thus, Solubility varies directly with Pressure

If S represents Solubility and P represents Pressure,

Then we can write that

S ∝ P

Introducing proportionality constant, k

S = kP

S/P = k

∴ We can write that

$\frac{S_{1} }{P_{1} } = \frac{S_{2} }{P_{2} }$

Where $S_{1}$ is the initial solubility

$P_{1}$ is the initial pressure

$S_{2}$ is the final solubility

$P_{2}$ is the final pressure

From the given information

$S_{1} = 0.890 \ g/L$

$P_{1} = 120 \ kPa$

$P_{2} = 100 \ kPa$

Putting the parameters into the formula, we get

$\frac{0.890}{120}=\frac{S_{2}}{100}$

$S_{2}= \frac{0.890 \times 100}{120}$

$S_{2}= 0.742 \ g/L$

Hence, the solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

Learn more on Solubility here: brainly.com/question/4529762

7 0

1 year ago