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How can you determine the type of radiation an atom emits as its nucleus decays

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1 answer:

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17 copper wires of length l and diameter d are connected in parallel to form a single composite conductor of resistance R. What

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Answer:

$\frac{D}{d} = 4.12$

Explanation:

As we know that resistance of one copper wire is given as

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$a = \pi (\frac{d}{2})^2$

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$r = \rho \frac{L}{\pi (\frac{d^2}{4})}$

$r = \rho \frac{4L}{\pi d^2}$

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$R = \rho \frac{4L}{\pi D^2}$

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now we have

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