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ZanzabumX [31]
3 years ago
13

Do wormholes exist ?? is it possible to traverse to the other side of the universe ?

Physics
1 answer:
Nastasia [14]3 years ago
8 0
Black holes is exists
Black holes is highly gravitional wave field in space
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19. The particles in an object move very quickly and are spread apart. Then they move slower and get slower and get closer toget
svlad2 [7]

Answer:

The transformation went from a gas to a solid which is a Deposition

Explanation:

Deposition is the phase transition in which gas transforms into solid without passing through the liquid phase. Deposition is a thermodynamic process. The reverse of deposition is sublimation and hence sometimes deposition is called desublimation.

4 0
4 years ago
Help with TEST pls!!
Westkost [7]

Answer:

12. D.

13. C.

14. H.

15. F.

16. G.

17. A.

18. D.

19. B.

20. C.

Hope this helps :)

Explanation:

8 0
3 years ago
In March 2006, two small satellites were discovered orbiting Pluto, one at a distance of 48,000 km and the other at 64,000 km. P
Natasha_Volkova [10]

Answer

given,

distance of first satellite = 48,000 Km

distance of second satellite = 64,000 Km

orbital period = 6.39 day

Using equation of time period

  T = \dfrac{2\pi r^{3/2}}{\sqrt{Gm_{pluto}}}

now, from the above equation we can say that only variable is Time period and r is the radii of orbit.

from the first satellite

   \dfrac{T_{charon}}{r^{3/2}_{charon}}=\dfrac{T_{sat1}}{r^{3/2}_{sat1}}

   T_{sat1}=\dfrac{T_{charon}\ r^{3/2}}{r^{3/2}_{charon}}

   T_{sat1}=\dfrac{6.39\times (48000)^{3/2}}{19600^{3/2}}

   T_{sat1}=24.5\ days

for second satellite

   T_{sat2}=\dfrac{T_{charon}\ r^{3/2}_{sat2}}{r^{3/2}_{charon}}

   T_{sat1}=\dfrac{6.39\times (64000)^{3/2}}{19600^{3/2}}

   T_{sat1}=37.7\ days

7 0
3 years ago
Which is colder, 0 degree C or 20 degrees F?
il63 [147K]
20 degrees F! 0 degrees C is equivalent to 32 degrees F, so 20 degrees F is colder.
7 0
3 years ago
Read 2 more answers
A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355 - L cans per min
Yuki888 [10]

Answer:

A. To find the mass flow rate.

We use= 220 x 0.355/ 60

= 1.3kg/s

B. Volume flowrate is = mass flowrate / density

But density is 1000kg/m³

= 1.3kg/s/ 1000kg/m³

= 0.0013m³/s

C. Flow speead at 1

= 0.0013m³/s / (2 x 10-2m)²

= 6.5m/s

D.flow speed at 2

0.0013m³/s / (8x 10-2m)²

=1.63m/s

E. Gauge pressure at point 1

= 152+ 1/1000 ( 1.63)²- 6.5² + 1000( 9.8) ( 0-1.35)

= 119kpa

7 0
3 years ago
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