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3 years ago

Find the current i in:

Physics

1 answer:

lawyer [7]3 years ago

5 0

Answer:

I = 24 A

Explanation:

This is Parallel Circuit and it is the first principle of parallel circuit that voltage will be equal in all components in the circuit

It includes 10 resistors Therefore the voltage across,

R1 = R2 = R3 = R4 = R5 = R6 = R7 = R8 = R9 = R10 = voltage in battery

We will apply Ohm's Law to each resistor to find its current because we know the voltage across each resistor is 12 V and the resistance of each resistor is 5Ω

I (R1) = E (R1) / R1

I (R1) = 12v / 5Ω

I (R1) = 2.4 A

The value resistance E of all resistors are same therefore by applying the formula above the value of current in all resistors will be 2.4 A

The Total current in the circuit will be

I (total) = I (1) + I (2) + I (3) + I (4) + I (5) + I (6) + I (7) + I (8) + I (9) + I (10)

I (total) = 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4

I (total) = 24 A

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stellarik [79]

Answer:

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3 years ago

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Jack observed his coworker Jane crying when she was called into the boss's office. Jack thinks that crying at work is a sign of

ivann1987 [24]

Jack could be displaying sexism

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3 years ago

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Convert <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%280.779mg%29%28min%29%7D%7BL%7D" id="TexFormula1" title="\frac{(0.779mg)(mi

Orlov [11]

The number converted is $0.0467 \frac{(kg)(s)}{m^3}$

Explanation:

In order to convert from the original units to the final units, we have to keep in mind the following conversion factors:

$1 kg = 1000 g = 10^6 mg$

$1 min = 60 s$

$1 m^3 = 1000 L$

The original unit that we have is

$\frac{mg\cdot min}{L}$

Therefore, it can be rewritten as:

$=\frac{mg \frac{1}{10^6 mg/kg}\cdot min\cdot 60 s/min}{L\frac{1}{1000L/m^3}}=0.06 \frac{(kg)(s)}{m^3}$

Therefore, since the initial number was 0.779, the final value is

$0.779\cdot 0.06 \frac{(kg)(s)}{m^3}=0.0467 \frac{(kg)(s)}{m^3}$

#LearnwithBrainly

5 0

4 years ago

The compass of an airplane indicates that it is headed due north and its airspeed indicator shows that it is moving through the

yarga [219]

Answer:

Airplane speed relative to the ground is 260 km/h and θ = 22.6º direction from north to east

Explanation:

This is a problem of vector composition, a very practical method is to decompose the vectors with respect to an xy reference system, perform the sum of each component and then with the Pythagorean theorem and trigonometry find the result.

Let's take the north direction with the Y axis and the east direction as the X axis

Vy = 240 km / h airplane

Vx = 100 Km / h wind

a) See the annex

Analytical calculation of the magnitude of the speed and direction of the aircraft

V² = Vx² + Vy²

V = √ (240² + 100²)

V = 260 km/h

Airplane speed relative to the ground is 260 km/h

Tan θ = Vy / Vx

tan θ = 100/240

θ = 22.6º

Direction from north to eastb

b) What direction should the pilot have so that the resulting northbound

Vo = 240 km/h airplane

Vox = Vo cos θ

Voy = Vo sin θ

Vx = 100 km / h wind

To travel north the speeds the x axis (East) must add zero

Vx -Vox = 0

Vx = Vox = Vo cos θ

100 = 240 cos θ

θ = cos⁻¹ (100/240)

θ = 65.7º

North to West Direction

The speed in that case would be

V² = Vx² + Vy²

To go north we must find Vy

Vy² = V² - Vx²

Vy = √( 240² - 100²)

Vy = 218.2 km / h

8 0

4 years ago

An 888.0 kg elevator is moving downward with a velocity of 0.800 m/s. It decelerates uniformly and comes to a stop in a distance

bagirrra123 [75]

Answer:

The value of tension on the cable T = 1065.6 N

Explanation:

Mass = 888 kg

Initial velocity ( u )= 0.8 $\frac{m}{sec}$

Final velocity ( V ) = 0

Distance traveled before come to rest = 0.2667 m

Now use third law of motion $V^{2}$ = $u^{2}$ - 2 a s

Put all the values in above formula we get,

⇒ 0 = $0.8^{2}$ - 2 × a ×0.2667

⇒ a = 1.2 $\frac{m}{sec^{2} }$

This is the deceleration of the box.

Tension in the cable is given by T = F = m × a

Put all the values in above formula we get,

T = 888 × 1.2

T = 1065.6 N

This is the value of tension on the cable.

5 0

4 years ago