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andrew11 [14]
3 years ago
12

calculate the frequency in hertz of electromagnetic radiation that has a wavelength of 720.0 nm. (c= 3.00 X 10^8 m/s)

Chemistry
1 answer:
Vikentia [17]3 years ago
6 0

Answer:

f=216s^{-1}=216Hz

Explanation:

Hello.

In this case, the relationship between wavelength, speed of light and frequency is:

\lambda=\frac{c }{f}

It means that solving for the frequency, we obtain:

f=c*\lambda

Thus, for the given 720-nm wavelength and the speed of light, the frequency is:

f=3.00x10^8\frac{m}{s}*720.0nm*\frac{1x10^{-9}m}{1nm}\\  \\f=216s^{-1}=216Hz

Best regards.

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How many moles are contained in 2.3 liters of a 1.2M solution?
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Answer:

\boxed {\boxed {\sf 2.76 \ mol}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

molarity = \frac {moles}{liters}

We know the molarity is 1.2 M (mol\liter) and there are 2.3 liters of solution. Substitute the known values into the formula.

1.2 \ mol/liter= \frac {x}{2.3 \ liters}

Since we are solving for x, we must isolate the variable. It is being divided by 2.3 and the inverse of division is multiplication. Multiply both sides by 2.3 liters.

2.3 \ liters *1.2 \ mol/liter= \frac {x}{2.3 \ liters}* 2.3 \ liters\\2.3 *1.2 \ mol= x\\2.76 \ mol =x

In a solution with a molarity of 1.2 and 2.3 liters of solution, there are 2.76 moles.

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3 years ago
Draw the structures of the major 1,2 and 1,4-products formed by reaction of 1 mole of Br2 with 3-methyl-2,4-hexadiene. Assume th
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3 years ago
Hich sentence most accurately describes electrically charged objects?
Ket [755]

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They attract or repel other charged objects without touching them.

Explanation:

My chemistry teacher always says like repels like opposite attracts.

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What is the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol)?
NemiM [27]

the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol) is 1.36g

The reaction is 3 MnO2 + 4 Al ------ 2Al2o3+ Mn

3 mole of manganese oxide give 2 moles of aluminum oxide so by the reaction n( MnO2)/3 =n(al203)2

the formula is n= mass/M so, now substituting values

m (Al2O3)= m(MnO2) X 2 X M (Al2O3) / M(MnO2 X3

so, by substituting values, 2 X101.96 X1.74g / 3 X 86.94 =1.36g

so mass of aluminum oxide obtained = 1.36g

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brainly.com/question/19694949

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2 years ago
Examination of the first few successive ionization energies for a given element usually reveals a large jump between two ionizat
gladu [14]

Answer:

See Explanation

Explanation:

Ionization energy refers to the energy required to remove an electron from an atom. Metals have lower ionization energy than non metals since ionization energy increases across a period.

One thing that we must have in mind is that it takes much more energy to remove an electron from an inner filled shell than it takes to remove an electron from an outermost incompletely filled shell.

Now let us consider the case of magnesium which has two outermost electrons. Between IE2 and IE3 we have now moved to an inner filled shell(IE3 refers to removal of electrons from the inner second shell) and a lot of energy is required to remove an electron from this inner filled shell, hence the jump.

For aluminium having three outermost electrons, there is a jump between IE3 and IE4 because IE4 deals with electron removal from a second inner filled shell and a lot of energy is involved in the process hence the jump.

Hence a jump occurs each time electrons are removed from an inner filled shell.

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