Question

What weight of Tris-HCL (MW=121) is required to prepare 2L of a 15% w/v solution?

Answer 1

Explanation:

Percentage w/v means that weight of solute present in 100 ml of a solution. Hence, 15% w/v means that 15 gram of solute per 100 ml of solution.

Hence, for 2 L (or 2000 mL) preparation the amount of mass will be calculated as follows.

                 $\frac{15 g}{100 ml} \times 2000 ml$

                  = 300 g

Thus, we can conclude that weight of Tris-HCL required is 300 g.