The appropriate response is the Aneroid barometer. This kind of gauge has an incompletely cleared chamber that progressions shape, packing as barometrical weight increments and growing as weight declines.
I hope the answer will help you.
Answer:
Option C. 30 m
Explanation:
From the graph given in the question above,
At t = 1 s,
The displacement of the car is 10 m
At t = 4 s
The displacement of the car is 40 m
Thus, we can simply calculate the displacement of the car between t = 1 and t = 4 by calculating the difference in the displacement at the various time. This is illustrated below:
Displacement at t = 1 s (d1) = 10 m
Displacement at t= 4 s (d2) = 40
Displacement between t = 1 and t = 4 (ΔD) =?
ΔD = d2 – d1
ΔD = 40 – 10
ΔD = 30 m.
Therefore, the displacement of the car between t = 1 and t = 4 is 30 m.
The answer is m/s hope it helps
Answer:
<em>The first choice (32m/s) is the closest to the answer</em>
Explanation:
The magnitude of a vector is the distance between the initial and the end point of the vector.
Being Vx and Vy the horizontal and vertical components of the vector V respectively, the magnitude of V is calculated as:

The components of the velocity of the physics student's projectile launcher are Vx=28 m/s and Vy=15 m/s.
Calculate the magnitude of the velocity:




The first choice (32m/s) is the closest to the answer
Answer:
The answer to the question is
The ball will go 0.14 meters high if the gun is aimed vertically
Explanation:
The energy in the spring → Energy, E = 
Where E = energy in the spring
k = Spring constant
x = Spring compression or stretch
Therefore E = 
The spring energy is transferred to the ball as kinetic energy based on the first law of thermodynamics which states that energy is neither created nor destroyed
Kinetic energy = KE = 
From which v =
=
= 1.66 m/s
from v² =u² - 2·a·S
Where v = final velocity = 0 m/s
u = initial velocity = 1.66 m/s
a = g = Acceleration due to gravity
S = height
Therefore 0 = 1.66² - 2×9.81×S
or S = 1.66² ÷ (2×9.81) = 0.14 m