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ale4655 [162]
3 years ago
6

What is the resultant force acting on an object? The first force is 45 N West and the second is 23 N East.

Physics
1 answer:
Paul [167]3 years ago
4 0

Answer:

22N West

Explanation:

45-23 because they are in opposite directions.

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A cell of e.m.f 1.5 v and internal resistance 2.5 ohm is connected in series with an ammeter of resistance 0.5 ohm and a resisto
sergejj [24]

Answer:

The current in the circuit is 0.15 Ampere

Explanation:

The given parameters of the cell are;

The electromotive force (e.m.f.) of the cell, E = 1.5 V

The resistance of the cell, r = 2.5 ohm

The resistance of the ammeter = 0.5 ohm

The resistance of the resistor = 7.0 ohm

The formula for the e.m.f., E of a cell is given as follows;

e.m.f. E = I·(R + r)

Where;

I = The current in the circuit

R = The sum of the resistances in the circuit = 7.0 Ω + 0.5 Ω + 2.5 Ω = 10 Ω

Therefore, we have;

The \ current \ in \ the \ circuit, \  I = \dfrac{E}{R + r}

Substituting the known values, gives;

I = \dfrac{1.5 \ V}{7 \ \Omega  + 0.5 \ \Omega  + 2.5 \ \Omega} = \dfrac{1.5 \ V}{10 \ \Omega} = 0.15 \ A

The current in the circuit, I = 0.15 Ampere.

6 0
3 years ago
In solving a physics problem you end up with m in the numerator and m/s in the denominator. The units for your answer are :_____
Vladimir [108]

Answer:

s

Explanation:

It is given that, a physics problem you end up with m in the numerator and m/s in the denominator. It would mean that,

\dfrac{\text{numerator}}{\text{denominator}}=\dfrac{m}{m/s}

m is metre and s is second

or

=\dfrac{m}{\dfrac{m}{s}}\\\\=\dfrac{s}{1}

so, the unit of the answer is <u>s</u>.

7 0
4 years ago
a vector a has components a x equals -5.00 m in a y equals 9.00 meters find the magnitude and the direction of the vector
Murrr4er [49]

Answer:

The magnitude = 10.30 m

The direction of the vector proceeds at angle of 119.05°

Explanation:

Given that:

A vector \bar A has component A_x = -5 m and A_y = 9 m

The magnitude of vector  \bar A can be represented as:

\bar A  = \sqrt{A_x^2 + A_y^2}

\bar A  = \sqrt{(-5)^2 + (9)^2}

\bar A  = \sqrt{25 + 81}

\bar A  = \sqrt{106}

\bar A  = 10.30 m

If we make \bar A  an angle \theta with y- axis:

Then;   tan \theta  = \frac{A_x}{A_y}

tan \theta  = \frac{5}{9}

tan \theta  = 0.555

\theta  = tan⁻¹ (0.555)

\theta  = 29.05°

Angle with positive x-axis = 90 + \theta  

= 90° + 29.05°

= 119.05°

5 0
3 years ago
An object will maintain a constant speed until a force acts on it true or false
Scorpion4ik [409]
<span>You do not require a force to keep something moving.  You only require a force to get it moving.  Or to stop it moving.  In your everyday experiences, something you get moving seems to come to a stop after you stop pushing it.  It is because there are forces (friction) that make it stop.  Without those forces, the object would just keep moving. So this would mean the answer would be True.</span>
3 0
3 years ago
Resistors and reactors, for use over 600 volts, shall not be installed in close enough proximity to combustible materials to con
suter [353]

Resistors and reactors, for use over 600 volts, shall not be installed in close enough proximity to combustible materials to constitute a fire hazard and shall have a clearance of not less than<u> 300 mm </u>from combustible materials.

Explanation:

  • The hazards associated with high power industrial resistors are primarily due to their open construction, which is necessary for cooling.
  • The exposed conductors which make up the resistors can be not only a shock hazard but also a thermal burn hazard.
  • When a resistor fails, it either goes open or the resistance increases. When the resistance increases, it can burn the board, or burn itself up.
  • Avoid touching non-flammable resistors in operation; the surface temperature ranges from approximately 350 °C to 400°C when utilized at the full rated value. Maintaining a surface temperature of 200°C or less will extend resistors service life.
  • Do not apply power to a circuit while measuring resistance. When you are finished using an ohmmeter, switch it to the OFF position if one is provided and remove the leads from the meter.
  • Always adjust the ohmmeter for 0 (or in shunt ohmmeter) after you change ranges before making the resistance measurement.

4 0
3 years ago
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