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Llana [10]
4 years ago
5

Calculate the volume of this regular solid.

Physics
2 answers:
tekilochka [14]4 years ago
4 0
Where are the calculations? please be more specific so we can helo you
olchik [2.2K]4 years ago
3 0

Answer:

its 42.41 cm^3 on edge.

Explanation:

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kozerog [31]

Newton's second equation of motion :-

S=ut+1/2at^2 [where, u is the initial velocity, a is the acceleration and t is the time interval]

This Equation simply finds a relation between distance travelled by a particle (classically) under uniform acceleration.

So let's see what pieces of information (bundles of equations) do we have with us, initially.

We have, a very primary equation with us,

dS/dt = v… (I)

(Considering motion in a straight line only)

And we also have the equation

dv/dt = a…(II)

Simply replacing the v in eqn (II) by eqn (I), we find

d2S/dt^2 = a…(III)

This is what we need to solve. It's easy.

You know,

d2S/dt^2 = d/dt(dS/dt) = a

⟹ dS/dt = ∫adt = at+c1

Since, dS/dt is the velocity of the particle,

Therefore, at t = 0, dS/dt|t = 0 = u

⟹ u = a∗0 + c1 = c1

⟹ c1 = u

Therefore, dS/dt = u + at

Thus, S = ∫(udt + atdt)

⟹ S = ut + 1/2at^2 +c^2

If say, the particle is already having a displacement S0 the moment you start measuring it's motion. Then, at t = 0, S = S0

This makes S = S0 +ut + 1/2at^2

Since, in most of the practical cases, we start measuring a motion when the particle starts displacing (i.e., when S0=0 ),

We get

S = ut + 1/2at^2

Hope it helps :)

5 0
3 years ago
What happens at a reverse fault plane?
melamori03 [73]
<span>B. Compression causes upward vertical movement.</span>
5 0
3 years ago
Read 2 more answers
Roberta is going over the form with a patient; the form includes such information as the name of the patient, the
velikii [3]

Answer:

encounter form

7 0
4 years ago
An object acted on by a constant force F moves from point 1 to point 2 and back again. The work done by the force F in this roun
aksik [14]

Answer:

F is non-conservative.

If F were conservative no work would be done in moving back to the original point.       F dot S = W     if the net distance is zero the work done is zero for a conservative force

7 0
3 years ago
Several different compounds can share the same empirical formula. The Molecular weight for three compounds with the empirical fo
Pie

Molecular formulas:

  1. CH₂O;
  2. C₂H₄O₂;
  3. C₆H₁₂O₆.
<h3>Explanation</h3>

The empirical formula of a compound tells only the ratio between atoms of each element. The empirical formula CH₂O indicates that in this compound,

  • for each C atom, there are
  • two H atoms, and
  • one O atom.

The molecular weight (molar mass) of the molecule depends on how many such sets of atoms in each molecule. The empirical formula doesn't tell anything about that number.

It's possible to <em>add</em> more of those sets of atoms to a molecular formula to increase its molar mass. For every extra set of those atoms added, the molar mass increase by the mass of that set of atoms. The mass of one mole of C atoms, two mole of H atoms, and one mole of O atoms is 12.0 + 2\times 1.0 + 16.0 = 30.0\;\text{g}.

  • CH₂O- 30.0 g/mol;
  • C₂H₄O₂- 30.0 + 30.0 = 2 × 30.0 = 60.0 g/mol;
  • C₃H₆O₃- 30.0 + 30.0 + 30.0 = 3 × 30.0 = 90.0 g/mol.

It takes one set of those atoms to achieve a molar mass of 30.0 g/mol. Hence the molecular formula CH₂O.

It takes two sets of those atoms to achieve a molar mass of 60.0 g/mol. Hence the molecular formula C₂H₄O₂.

It takes \dfrac{180.0}{30.0} = 6 sets of those atoms to achieve a molar mass of 180.0 g/mol. Hence the molecular formula C₆H₁₂O₆.

5 0
3 years ago
Read 2 more answers
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