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3 years ago

Locate the complete verbal phrase and identify its type.

2 answers:

7 0

won
adjective

Verb phrases are verbs that may function as a predicate, adjective, or adverb. 

(a) "That he said" is an adjective modifying "word". However, this contains the s ubject"he" and the verb "said". It is a clause and NOT a phrase. Phrases can only have either a verb or a noun.
(b) There's only one verb "was" but it does not come with a complement, object, modifier, or other verb. Hence, it's NOT a verb phrase. 
(c) "Shall be" consists of the modal shall and the be-verb be. This is a perfect example of a verb phrase that functions as a VERB PHRASE. 
(d) "Roared" and "charged" are two verbs referring to different subjects. They do not come with a complement, object, modifier, or another verb. Hence, they're NOT a verb phrase. "As the bull charged" is a clause and not a phrase.

rodikova [14]3 years ago

5 0

The correct answer is:

Verbal Phrase: named Robert

Type: participial

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An ideal gas is in a sealed rigid container. the average kinetic energy of the gas molecules depends most on

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It depends most on the temperature of the gas.

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Please i need your help w/h/w you make the following measurements if an object:42kg, and 22m

Rufina [12.5K]

Answer:

$1.9 kg/m^3$

Explanation:

The density of an object is given by

$d=\frac{m}{V}$

where

m is the mass of the object

V is its volume

In this problem,

m = 42 kg

V = 22 m^3

Substituting into the equation, we find the object's density:

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3 years ago

A 650 kg steel beam is being pulled up by a crane with a force of 7020 N. What is the upwards acceleration of the beam?

zimovet [89]

Answer: 1 m/s^2

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n= w+ma

n= Mg+Ma

7020 = (650)(9.8)+650a

7020 = 6370+ 650a

650=650a

A= 1 m/s^2

8 0

3 years ago

The erg is a unit of work in units of centimeters (cm), grams (g), and seconds (s), and 1 erg=1 g⋅cm^2/s^2 . Recall that the SI

OverLord2011 [107]

For the given problem, the amount of work done expressed in ergs is 3200 ergs.

Answer: Option A

Explanation:

The work done on an objects are the force acting on it to move the object to a particular distance. So, work done on the object will be directly proportional to the force acting on it and the displacement.

Here, the force acting on the object is given as 0.010 N and the displacement of the object is 0.032 m. So, the work done on the object is

$\text { Work done }=\text { Force } \times \text { displacement }$

$\text { Work done }=0.010 \mathrm{N} \times 0.032 \mathrm{m}=0.00032 \mathrm{Nm}$

It is known that $1 N=1 \mathrm{kg} \mathrm{ms}^{-2}$

So, the work done can be expressed in $k g m s^{-2}$ as,

$\text { Work done }=0.00032 \mathrm{kgm}^{2} \mathrm{s}^{-2}$

It is known that $1 \mathrm{erg}=1 \mathrm{g} \mathrm{cm}^{2} / \mathrm{s}^{2}$ , so the conversion of units from Nm to erg will be done as follows:

$\text { Work done }=0.00032 \mathrm{kgm}^{2} \mathrm{s}^{-2} \times \frac{1000 \mathrm{g}}{1 \mathrm{kg}} \times \frac{100 * 100 \mathrm{cm}^{2}}{m^{2}}=3200 \mathrm{g} \mathrm{cm}^{2} \mathrm{s}^{-2}$

Thus, work done in ergs is 3200 ergs.

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Angelina_Jolie [31]

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