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4 years ago

What is a non example of element, compound, and pure substance

2 answers:

vladimir1956 [14]4 years ago

7 0

• Element non examples include all compounds, which are substances made when two different types of atoms form a chemical bond. Any material made by mixing elements is no longer an element. Anytime you see a chemical formula with more than one element symbol in it, it’s an element non example.

• The most popular non examples of a compound are gold, silver , and bronze.

• A pure element or compound contains only one substance, with no other substances mixed in. Inpure materials may be mixtures of elements, mixtures of compounds, or mixtures of elements and compounds.

Sveta_85 [38]4 years ago

3 0

Hmmm... Water? It's not an element. it's made of two so it's bi and not compound. It's not pure because it disperse and evaporates under heat. Pure substances are more like metals

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Decomposition of NI3 produces nitrogen gas and iodine. How many grams of the reactant would be required to react completely to g

VMariaS [17]

Answer:

Grams of the reactant would be required is 8.26 g

Explanation:

Decomposition of NI3 is :

2 NI3 (s) --------------------> N2 (g)............... +..................... 3 I2 (g)

2 mol..................................1 mol.........................................3 mol

2 x 394.7 g/mol..............28 g/mol....................................3 x 253.8 g/mol

789.4 g...............................28 g...........................................761.4 g

From chemical equation it is cleared that

761.4 g of iodine is obtained from = 789.4 g of NI3

Therefore,

7.97 g of iodine is obtained from = 789.4 g x 7.97 g / 761.4 of NI3

= 6291.518 / 761.4 of NI3

= 8.26 g of NI3

Hence

Grams of the reactant would be required = 8.26 g

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3 years ago

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andreyandreev [35.5K]

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3 years ago

Why can non polar covalent compounds dissolve in alcohol?

aleksklad [387]

Answer:

Non-polar solvents cannot dissolve polar compounds since no opposite charges exist and the polar compound is not attracted.

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7 0

2 years ago

Read 2 more answers

Thea is doing a chemistry experiment. The instructions say she needs to use pure water. Hamza offer her a bottle labelled “100%

Diano4ka-milaya [45]

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3 years ago

Citric acid is a naturally occurring compound. what orbitals are used to form each indicated bond? be sure to answer all parts.2

Rina8888 [55]

Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.

Answer 1) σ Bond a : C has $SP^{2}$ O has $SP^{2}$ .

Explanation : The orbitals of oxygen and carbon which are involved in $SP^{2}$ hybridization to form sigma bonds. This is observed at 'a' position in the citric acid molecule.

Answer 2) π Bond a: C has π orbitals and O also has π orbitals.

Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.

Answer 3) Bond b: O $SP^{3}$ H has only S orbital involved in bonding.

Explanation : The bonding at 'b' position involves oxygen $SP^{3}$ hydrogen atoms in it. It has $SP^{3}$ hybridized orbitals and S orbital of hydrogen involved in the bonding.

Answer 4) Bond c: C is $SP^{3}$ O is also $SP^{3}$

Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of $SP^{3}$ hybridized bonds.

Answer 5) Bond d: C atom has $SP^{3}$ C atom has $SP^{3}$

Explanation : At the position of 'd' the bonding between two carbon atoms is found to be $SP^{3}$ . Therefore, the orbitals that undergo $SP^{3}$ hybridization are $SP^{3}$ .

Answer 6) Bond e : C1 containing O $SP^{2}$

C2 is $SP^{3}$

Explanation : The carbon atom which contains oxygen along with a double bond has $SP^{2}$ hybridized orbitals involved in the bonding process; whereas the carbon at C2 has $SP^{3}$ hybridized orbitals involved during the bonding. This is for the 'e' position.

7 0

4 years ago