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Likurg_2 [28]
1 year ago
9

The two most abundant atmospheric gases react to a tiny extent at 298 K in the presence of a catalyst:N₂(g) + O₂(g) ⇆ 2NO(g) Kp

= 4.35 ˣ 10⁻³¹a) What are the equilibrium pressures of the three gases when the atmospheric partial pressures of O₂ (0.210 atm) and of N₂ (0.780 atm) are put into an evacuated 1.00-L flask at 298 K with the catalyst?
Chemistry
1 answer:
kogti [31]1 year ago
8 0

A reversible reaction is defined as a chemical reaction where the reactants and the products react together to give the reactants back.

<h3>Reversible reaction</h3>

The reaction is:

H2​O+O⟶2OH ,      ΔH=−72kJ; Ea​=77kJ/mol

2OH⟶H2​O+O ,      Ea​=?   (Refer to Image)

Ea​ for the reverse reaction

=(Ea​)forward​+ΔH

=77+(−72)=5kJ

<h3>What is reverse reaction equation?</h3>

A reversible reaction is denoted by a double arrow pointing both directions in a chemical equation. For example, a two reagent, two product equation would be written as. A + B ⇆ C + D.  In simple words, we can say that it is a reaction involving the simultaneous conversion of reactants to products and vice versa.

To learn more about  reverse reaction visit the link

brainly.com/question/16614705

#SPJ4

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A 0.708 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M ( s ) + H 2 SO 4 ( aq ) ⟶ MSO 4
ollegr [7]

Answer:

The metal has a molar mass of 65.37 g/mol

Explanation:

Step 1: Data given

Mass of the metal = 0.708 grams

Volume of hydrogen = 275 mL = 0.275 L

Atmospheric pressure = 1.0079 bar = 0.9947 atm

Temperature = 25°C

Vapor pressure of water at 25 °C = 0.03167 bar = 0.03126 atm

Step 2: The balanced equation

M(s) + H2SO4(aq) ⟶ MSO4 (aq) + H2(g)

Step 3: Calculate pH2

Atmospheric pressure = vapor pressure of water + pressure of H2

0.9947 atm = 0.03126 atm + pressure of H2

Pressure of H2 = 0.9947 - 0.03126

Pressure of H2 = 0.96344 atm

Step 4: Calculate moles of H2

p*V=n*R*T

⇒ with p = The pressure of H2 = 0.96344 atm

⇒ with V = the volume of H2 = 0.275 L

⇒ with n = the number of moles H2 = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 25°C = 298 Kelvin

n = (p*V)/(R*T)

n = (0.96344 * 0.275)/(0.08206*298)

n = 0.01083 moles

Step 5: Calculate moles of M

For 1 mole of H2 produced, we need 1 mole M

For 0.0108 moles of H2 we need 0.01083 moles of M

Step 6: Calculate molar mass of M

Molar mass M = Mass M / moles M

Molar mass M = 0.708 grams / 0.01083 moles

Molar mass M = 65.37 g/mol

The metal has a molar mass of 65.37 g/mol

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