Answer:
Final vertical velocity = -29m/s
Horizontal distance = 100m
Height = 20.41m
Explanation:
1. The vertical final velocity can be calculated thus: vy = vyo - gt
Where;
vy = vertical velocity (m/s)
vyo = vertical initial velocity (20m/s)
g = acceleration due to gravity (9.8m/s²)
t = time (5s)
Hence, vy = vyo - gt
vy = 20 - (9.8 × 5)
vy = 20 - 49
vy = -29m/s
2. x = V0 x t
Where;
x = horizontal distance (m)
Vo = initial velocity
t = time (s)
x = 20 × 5
x = 100m
3. Maximum height = (voy)²/2g
= 20²/ 2 × 9.8
= 400/19.6
= 20.41m
Do cherry popsicles freeze slower than orange popsicles
Answer:
Generally, the lowest overtone for a pipe open at one end and closed would be at y / 4 where y represents lambda, the wavelength.
Since F (frequency) = c / y Speed/wavelength
F2 / F1 = y1 / y2 because c is the same in both cases
F2 = y1/y2 * F1
F2 = 3 F1 = 750 /sec
Note that L = y1 / 4 = 3 y2 / 4 for these wavelengths to fit in the pipe
and y1 = 3 y2
Answer:
a) 2.87 m/s
b) 3.23 m/s
Explanation:
The avergare velocity can be found dividing the length traveled d by the total time t.
a)
For the first part we easily know the total traveled length which is:
d = 50.2 m + 50.2 m = 100.4 m
The time can be found dividing the distance by the velocity:
t1 = 50.2 m / 2.21 m/s = 22.7149 s
t2 = 50.2 m / 4.11 m/s = 12.2141 s
t = t1 +t2 = 34.9290 s
Therefore, the average velocity is:
v = d/t =2.87 m/s
b)
Here we can easily know the total time:
t = 1 min + 1.16 min = 129.6 s
Now the distance wil be found multiplying each velocity by the time it has travelled:
d1 = 2.21 m/s * 60 s = 132.6 m
d2 = 4.11 m/s *(1.16 * 60 s) = 286.056 m
d = 418.656 m
Therefore, the average velocity is:
v = d/t =3.23 m/s
