Which will react faster NaCl or CH3COOH?

What is the molar solubility of aucl3 (ksp = 3. 2 x 10-23) in a 0. 013 m solution of magnesium chloride (a soluble salt)?

Inessa [10]

The molar solubility of AuCl₃ in a 0.013 M solution of magnesium chloride is 1.81×10⁻²⁸M.

The solubility product constant, Ksp, is the equilibrium constant for a solid substance dissolving in an aqueous solution. And for the AuCl₃, Ksp will be written as: Ksp = [Au³⁺][Cl⁻]³

Let the solubility of the AuCl₃ in 0.013M solution of magnesium chloride is x, of Au³⁺ is x and of Cl⁻ is 3x. But we know that MgCl₂ is a strong electrolyte and it completely dissociates into its ions and will produce 2 moles of chloride ions. For this solution let we consider the volume is 1 liter then the concentration of chloride ions in MgCl₂ is 2(0.013)=0.026M.

So, in MgCl₂ solution concentration of Cl⁻ becomes = 3x + 0.026.

Value of Ksp for AuCl₃ = 3.2 × 10⁻²³

On putting all values on the Ksp equation, we get

Ksp = (x)(3x + 0.026)³

Value of 3x is negligible as compared to the 0.026, so the equation becomes

3.2 × 10⁻²³ = (x)(0.026)³

x = 3.2×10⁻²³ / (0.026)³

x = 1.81×10⁻²⁸M

Hence the molar solubility of AuCl₃ in 0.010M MgCl₂ is 1.81×10⁻²⁸M.

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4 0

3 years ago

What is the solution to the problem expressed to the correct number of significant figures

quester [9]

I don't know what the problem is, but here are some rues to help you out:

All non-zero figures are significant
When a zero falls between non-zero digits, that zero is significant.
When a zero falls after a decimal point, that zero is significant.
When multiplying and dividing significant figures, the answer is limited to the number of sig figs equal to the least number of sig figs in the problem.
When adding and subtracting, the answer is limited to the number of decimal places in the number with the least number of decimal places.

4 0

4 years ago

Elemental analysis of the unknown gas from part a revealed that it is 30.45% n and 69.55% o. what is the molecular formula for t

Gnesinka [82]

Assuming we have 100 g of sample

30.45/MW of N 14g = 2.175

69.55/MW of O 16g = 4.34

4.34/2.185 = 2

for every 1 mole of N we have 2 moles of O

so the empirical formula would be NO2

without having the molecular weight of the entire molecule the molecular formula can not be determined with the information in your question

6 0

3 years ago

4. The following occurs when heat energy is removed: Gas --A-> Liquid-B--> Solid.

Misha Larkins [42]

Answer: The phase change for A and B respectively is condensation, freezing.

Explanation:

A process in which gaseous state of a substance converts into liquid state is called condensation.

For example, conversion of steam into water.

A process in which liquid state of a substance converts into solid state is called freezing.

For example, conversion of liquid water into ice.

Thus, we can conclude that the phase change for A and B respectively is condensation and freezing.

6 0

3 years ago

Samples of three different compounds were analyzed and the masses of each element were determined.

Dafna1 [17]

First, you have to convert mass to moles by making use of molecular weights [N = 14 g/mol and O = 16 g/mol)

A.
5.6/14 = 0.4 mol N
3.2/16 = 0.2 mol O
mol ratio = 2 mol N/1 mol O => N2O

B.
3.5/14 = 0.25 mol N
8.0/16 = 0.5 mol O
mol ratio = 1 mol N/2 mol O => NO2

C.
1.4/14 = 0.1 mol N
4.0/16 = 0.25 mol O
mol ratio = 2 mol N/5 mol O => N2O5

6 0

3 years ago