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malfutka [58]
3 years ago
12

How do I calculate initial speed by using the slope of a graph? The graph shows the relationship between S {(sin2ϴ)/g} and the a

verage range of a projectile in meters.
Physics
1 answer:
Orlov [11]3 years ago
3 0
The formula for slope is y=mx+b
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lesya692 [45]
Have an excuse ready so you can leave 
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3 years ago
Read 2 more answers
A 500-kilogram sports car accelerates uniformly from rest, reaching a speed of 30 meters per second in 6 seconds. During the 6 s
AlekseyPX

Answer:

90 m

Explanation:

Given that

Mass of the car, m = 500 kg

Initial speed of the car, u = 0 m/s

Final speed of the car, v = 30 m/s

Time taken to travel, t = 6 s

average speed v = (30 + 0) / 2 = 15

We are going to be using the most very basic equations to solve this.

speed can be defined as the ratio of distance with respect to time.

v = d/t, Where

v = speed.

d = distance travelled and

t = time taken

if we invert this, we can get that

d = v.t

distance is multiplication of speed and time. We will be using the average speed we calculated above, so

Distance travelled in 6 s,

d = 15 * 6

d = 90 m.

therefore, the distance travelled by the car in this 6 s is 90 m

4 0
3 years ago
Draw a Lewis dot structure for Hf<br><br>​
Serjik [45]

Answer:

There!!

Explanation:

mark me brainliest!!

3 0
2 years ago
A dead organism is the same as a nonliving thing in science. <br> Fact: <br> Evidence:
nikitadnepr [17]

No that is false

Because its a organism. Which means at one point it was a live. It just died. You cant die if you were never alive. So that means that at one time was living.

But nonliving thing in science is like a piece of plastic cant breath eat die non living

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4 0
3 years ago
After an eye examination, you put some eyedrops on your sensitive eyes. The cornea (the front part of the eye) has an index of r
mina [271]

Answer:

t = 103.45 n m

Explanation:

given,

refractive index of cornea = 1.38

refractive index of eye drop = 1.45

wavelength of refractive index = 600 nm

refractive index of eye drop is greater than refractive index of cornea and the air.

Formula used in this case

for constructive interference

2 n t = (m + \dfrac{1}{2})\lambda

At m = 0 for the minimum thickness, so

2\times 1.45 \times t = (0 + 0.5)\times 600

2.9 \times t =300

t =\dfrac{300}{2.9}

t = 103.45 n m

the minimum thickness of the film of eyedrops t = 103.45 n m

6 0
3 years ago
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