A colourless obourless gaseous elements that gives a red Glow in a vacuum tube
A. nonmetallic univalent elements that is normal a colourless
Answer:
A) The reaction mixture contains mostly products at equilibrium
Explanation:
For the general reaction
Reactants ⇌ Products
The equilibrium constant is
![K_{\text{eq}} = \dfrac{\text{[Products]}}{\text{[Reactants]}}](https://tex.z-dn.net/?f=K_%7B%5Ctext%7Beq%7D%7D%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BProducts%5D%7D%7D%7B%5Ctext%7B%5BReactants%5D%7D%7D)
Thus, if K is large, the concentration of products is greater than that of reactants.
The reaction mixture will contain mostly products at equilibrium.
C) and E) are wrong. The equilibrium constant gives us information only on the position of equilibrium, not on how fast it is achieved.
P₁V₁ = P₂V₂
Convert 473ml > L

(1atm)(1.00L) = (0.473L)P₂
Divide by (0.473L)

Solve for 2.11atm
Answer:
I think its, balanced chemical equations
Explanation:
Answer:
A solution that is 0.10 M HC2H3O2 and 0.10 M LiC2H3O2 is a good buffer system.
Explanation:
A buffer is defined as the mixture between a weak acid and its conjugate base or vice versa.
For the solutions:
0.10 M HF and 0.10 M LiC2H3O2. HF is a weak acid but LiC2H3O2 is the conjugate base of the weak acid (HC2H3O2, acetic acid).
0.10 M HC2H3O2 and 0.10 M LiC2H3O2. Here, you have a mixture of HC2H3O2, acetic acid, weak acid, and LiC2H3O2 is its conjugate base. Thus, <em>this is a good buffer system</em>
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0.10 M LiOH and 0.10 M KOH. LiOH ans KOH are both strong bases.
0.10 M HF and 0.10 M NH4+. Again, HF is a weak acid but NH4+ is the conjugate acid of a weak base (NH3).