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larisa [96]
3 years ago
5

Which kind of statement distinguishes a term from all other terms?

Chemistry
1 answer:
Goshia [24]3 years ago
6 0
I believe the answer is a definition. 
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How does a negative ion differ from a positive?
Ilya [14]
A negative ion or anion is an electrically charged atom or group of atoms that are formed by gaining one or more electrons. Whereas a positive ion or cation is an electrically charged atom or group of atoms that are formed by losing one or more electrons. 
The losing and gaining all occurs on the outermost shell. 
7 0
3 years ago
What is the correct formula for combining Mg2+ and Br1+
True [87]

Answer: The correct formula is MgBr_2

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

Here magnesium is having an oxidation state of +2 called as Mg^{2+} cation and bromine Br^{-} is an anion with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral MgBr_2.

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic bond.

6 0
2 years ago
Help please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
tangare [24]

Answer:

A

Explanation:

4 0
3 years ago
Read 2 more answers
Hi i need help. Select all the statements that are true.
motikmotik

Answer:

A, C, E

Explanation:

hope this helps

7 0
3 years ago
Read 2 more answers
Consider the insoluble compound nickel(II) hydroxide , Ni(OH)2 . The nickel ion also forms a complex with cyanide ions . Write a
natali 33 [55]

Answer: Equilibrium constant for this reaction is 2.8 \times 10^{15}.

Explanation:

Chemical reaction equation for the formation of nickel cyanide complex is as follows.

Ni(OH)_{2}(s) + 4CN^{-}(aq) \rightleftharpoons [Ni(CN)_{4}^{2-}](aq) + 2OH^{-}(aq)

We know that,

      K = K_{f} \times K_{sp}

We are given that, K_{f} = 1.0 \times 10^{31}

and,    K_{sp} = 2.8 \times 10^{-16}

Hence, we will calculate the value of K as follows.

     K = K_{f} \times K_{sp}

     K = (1.0 \times 10^{31}) \times (2.8 \times 10^{-16})

        = 2.8 \times 10^{15}

Thus, we can conclude that equilibrium constant for this reaction is 2.8 \times 10^{15}.

4 0
2 years ago
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