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3 years ago

5

Suppose that a meter stick is balanced at its center. A 0.24 kg mass is then positioned at the 6-cm mark. At what cm mark mus

t a 0.35 kg mass be placed to balance the 0.24 kg mass? (NEVER include units with the answer to ANY numerical question.)

1 answer:

Scilla [17]3 years ago

8 0

Answer:

80.17 cm

Explanation:

Taking moments of forces about the center, the total clockwise moments is equal to the total counter clockwise moment:

Force * distance (counter clockwise) = force * distance (clockwise)

0.24 * 9.8 * (50 - 6) = 0.35 * 9.8 * (x - 50)

0.24 * 44 = 3.43x - 171.5

103.5 = 3.43x - 171.5

=> 3.43x = 103.5 + 171.5

3.43x = 275

x = 275/3.43 = 80.17 cm

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2 years ago

A long, current-carrying solenoid with an air core has 1800 turns per meter of length and a radius of 0.0165 m. A coil of 210 tu

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From the question we are told that

The number of turns per unit length is $N = 1800$

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The number of turns of the solenoid is $N_s = 210 \ turns$

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$M = \mu_o * N * N_s * A$

Where A is the cross-sectional area of the system which is mathematically represented as

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3 years ago

An electron is released from rest at a distance of 0.470 m from a large insulating sheet of charge that has uniform surface char

ArbitrLikvidat [17]

Answer:

Part a)

$W = 1.58 \times 10^{-20} J$

Part b)

$v = 1.86 \times 10^5 m/s$

Explanation:

Part a)

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So work done is given as

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Part b)

Now we know that work done by all forces = change in kinetic energy of the electron

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