1. The time taken for the car to reach a velocity of 60 m/s is 8.57 s
2. The distance travelled during the time is 257.14 m
<h3>What is acceleration? </h3>
The acceleration of an object is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
- a is the acceleration
- v is the final velocity
- u is the initial velocity
- t is the time
1. How to determine the time
- Initial velocity (u) = 0 m/s
- Acceleration (a) = 7 m/s²
- Final velocity (v) = 60 m/s
- Time (t) =?
a = (v – u) / t
Thus,
t = (v – u) / a
t = (60 – 0) / 7
t = 8.57 s
2. How to determine the distance
- Initial velocity (u) = 0 m/s
- Acceleration (a) = 7 m/s²
- Final velocity (v) = 60 m/s
- Distance (s) = ?
v² = u² + 2as
60² = 0² + (2 × 7 × s)
3600 = 0 + 14s
3600 = 14s
Divide both sides by 14
s = 3600 / 14
s = 257.14 m
Learn more about acceleration and velocity:
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Oxygen and carbon dioxide
The frequency of the wave is 4 Hz
Answer:
The speed of the large cart after collision is 0.301 m/s.
Explanation:
Given that,
Mass of the cart, 
Initial speed of the cart, 
Mass of the larger cart, 
Initial speed of the larger cart, 
After the collision,
Final speed of the smaller cart, 
(as its recolis)
To find,
The speed of the large cart after collision.
Solution,
Let 
is the speed of the large cart after collision. It can be calculated using conservation of momentum as :
So, the speed of the large cart after collision is 0.301 m/s.
