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2 years ago

PLEASE HURRY!!!!!! 14 points

Chemistry

1 answer:

neonofarm [45]2 years ago

5 0

Answer:

a. Charle's Law

b. Kelvin

c. 605 K

Explanation:

Charle's law deals with volume and temp. Always change to Kelvin, unless otherwise noted. Use the formula V1/T1=V2/T2 and rearrange to fit problem.

- Hope that helped! Let me know if you want to work this through step by step.

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15.3 g of nano3 were dissolved in 100g of water in a calorimeter. The temperature of the water drops from 25.00°c to 21.56°c. Ca

Arturiano [62]

Answer:

0.259 kJ/mol ≅ 0.26 kJ/mol.

Explanation:

To solve this problem, we can use the relation:

where, Q is the amount of heat absorbed by ice (Q = ??? J).

m is the mass of the ice (m = 100.0 g).

c is the specific heat of water (c of ice = 4.186 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 21.56°C - 25.0°C = -3.44°C).

∴ Q = (100.0 g)(4.186 J/g.°C)(-3.44°C) = -1440 J = -1.44 kJ.

n = mass/molar mass = (100.0 g)/(18.0 g/mol) = 5.556 mol.

∴ ΔH = (-1.44 kJ)/(5.556 mol) = 0.259 kJ/mol ≅ 0.26 kJ/mol.

3 0

3 years ago

A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The

V125BC [204]

Taking into account the definition of calorimetry, the specific heat of metal is 0.165 $\frac{cal}{gC}$ .

<h3>Definition of calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

Q is the heat exchanged by a body of mass m.
C is the specific heat substance.
ΔT is the temperature variation.

<h3>Specific heat capacity of the metal</h3>

In this case, you know:

For metal:

Mass of metal = 50 g
Initial temperature of metal= 45 °C
Final temperature of metal= 11.08 ºC
Specific heat of metal= ?

For water:

Mass of water = 250 g
Initial temperature of water= 10 ºC
Final temperature of water= 11.08 ºC
Specific heat of water = 1.035 $\frac{cal}{gC}$

Replacing in the expression to calculate heat exchanges:

For metal: Qmetal= Specific heat of metal× 50 g× (11.08 C - 45 C)

For water: Qwater= 1.035 $\frac{cal}{gC}$ × 250 g× (11.08 C - 10 C)

If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the gold gives up will be equal to the heat that the water receives. Therefore:

- Qmetal = + Qwater

- Specific heat of metal× 50 g× (11.08 C - 45 C)= 1.035 $\frac{cal}{gC}$ × 250 g× (11.08 C - 10 C)

Solving:

- Specific heat of metal× 50 g× (-33.92 C)= 1.035 $\frac{cal}{gC}$ × 250 g× 1.08 C

Specific heat of metal× 1696 g×C= 279.45 cal

Specific heat of metal= $\frac{279.45 cal}{1696 gC}$

<u><em>Specific heat of metal= 0.165 </em></u> $\frac{cal}{gC}$

Finally, the specific heat of metal is 0.165 $\frac{cal}{gC}$ .

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1 year ago

What four factors influence the rate of a homogeneous reaction.

Anika [276]

1) concentration or partial pressure of species
involved. 2) temperature • 3) presence of catalyst
4) nature of reactants.

5 0

2 years ago

Please help with any

lys-0071 [83]

10 down: Particle with no charge

Answer: Neutron

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3 years ago

How many moles of KNO3 are in 500 mL of 2. 0 M KNO3? mol KNO3.

8090 [49]

The moles can be defined as the mass of the substance with respect to molar mass. The moles of potassium nitrate is 1 mol.

<h3>How to calculate moles of a substance?</h3>

The moles of a compound can be calculated from:

$\rm Moles=\dfrac{Mass}{Molar\;mass}$

The molarity can be defined as the moles of solute in a liter of solution.

The molarity can be expressed as:

$\rm Molarity=\dfrac{Moles\;\times\;1000}{Volume\;(mL)}$

The molarity of potassium nitrate solution is 2 M, and the volume is 500 mL.

The moles of potassium nitrate is given as:

$\rm 2\;M=\dfrac{Moles\;\times\;1000}{500\;mL}\\ Moles=\dfrac{2\;\times\;500}{1000}\;mol\\ Moles=1\;mol$

The moles of potassium nitrate in 2 M, 500 mL solution are 1 mol.

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4 0

1 year ago