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Tresset [83]
3 years ago
14

How is the melting point of a substance recorded

Chemistry
1 answer:
GrogVix [38]3 years ago
6 0

1. slowly heat stubstance.

2. once the substance is at the most liqued state take the temp. that's the melting point of that subtance.

hope that helps, any other questions feel free to DM me dont wate your points. :)

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Please help this test ends in 30 min
RideAnS [48]

Answer:

Option C

CH₃CH₂CH₂COOH

Explanation:

Carbonxylic acids are compounds which has the general formula

R–COOH where R is an alkyl group.

Considering the options given in the question above,

For A:

CH₃CH₂OCH₂CH₃ is an ether compound with general formula ROR' where R and R' are both alkyl group.

For B:

CH₃CH₂CH₂CH₂OH is an alcohol with general formula ROH where R is an alkyl group.

For C:

CH₃CH₂CH₂COOH is a carbonxylic acid with general formula R–COOH where R is an alkyl group.

For D:

CH₃CH₂C=OCH₂CH₃ is a ketone compound with general formula RC=OR' where R and R' are both alkyl group

For E:

ClCH₂CH₂CH₂CH₂CH₂CH₂Br is simply an Alkyl halide with general formula XRX where X is an halogen (i.e F, Cl, Br or I) and R is an alkyl group.

From the above illustration, only option C contains a Carbonxylic compound.

8 0
3 years ago
Which of these forces does not act over a distance?
aleksandr82 [10.1K]

Answer:

D. Gravitational

Explanation:

correct answer

3 0
3 years ago
Read 2 more answers
True or False. Explain the false statements:
juin [17]
A. true
b. false
c. true
d. false
e. false
8 0
3 years ago
Find the oxidizing agent and the reducing agent.
Vladimir [108]
Oxidizing agent is that which is reduced and the reducing agent is that which is oxidized. Reduced is when the charged is decreased and oxidized when the charge is increased.

(1)  2Na + 2H2O(l) --> 2NaOH(aq) + H2(g)
The charge of Na in the reactant is 0 and the charge of Na in the NaOH is +1. Na is oxidized. Hence, it is the reducing agent. 

The charge of H in H2O is +1 while that in H2 is 0. H is reduced. Hence, it is the oxidizing agent.

(2)  C(s) + O2(g) --> CO2(g)

The charge of C in the reactant side is 0 and that its charge in CO2 is +4. C is oxidized. Hence, it is the reducing agent. 

The charge of O in O2 is 0 while in CO2, its charge is -2. O is reduced. Hence, it is the oxidizing agent.

(3)  2MnO⁻⁴ + SO2 + 2H2O --> 2Mn²⁺ + 5SO2⁻⁴ 4H⁺

The charge of Mn in MnO⁻⁴ is 4+ while its charge in Mn²⁺ is 2+. Mn is reduced. Hence, it is the oxidizing agent.

The charged of S in SO2 is -4 while its charge in SO₂⁻⁴ is 0. S is oxidized. Hence, it is the reducing agent. 
8 0
3 years ago
A male fish releases sperm cells into the water. One of the sperm cells unites with an egg from a female fish to form a new cell
Illusion [34]

Answer: Sexual

Explanation: Two parents produce an offspring with some traits from each parent

5 0
3 years ago
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