CH3NH2 + HOH ==> CH3NH3^+ + OH^-Which molecule/ion accepts a proton. That is the base. Which molecule/ion donates a proton. That is the acid.
A stable subatomic particle known by the symbol for "proton"
e elementary charge, p, H+, or 1H+ having a positive electric charge. Its mass is 1,836 times greater than an electron's mass and just a little bit less than that of a neutron (the proton–electron mass ratio). "Nucleons" refers to protons and neutrons together, each of which has a mass of roughly one atomic mass unit (particles present in atomic nuclei).
Each atom. has a nucleus. that contains one or more protons. In order to keep the atomic electrons bound, they offer the central attractive electrostatic force. An element's defining characteristic, known as the atomic number, is the number of protons in the nucleus (represented by the symbol Z)
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(3.5mol)(24.106 g/1mol c6h6) =84.371 g C6H6
Answer:
Explanation:
From the sorensen equation; pH = -Log[H+]
2.7 = -Log[H+]
H+ = 10^-2.7
H+ = 0.001995M = Hydrogen ion concentration
Basically, the more the charges, the higher the hydrogen ion concentration stand vice versa. +2 has the highest concentration.
Answer:
The correct answer is option a.
Explanation:

Equilibrium concentration cadmium ions = ![[Cd^{2+}]=0.0585 M](https://tex.z-dn.net/?f=%5BCd%5E%7B2%2B%7D%5D%3D0.0585%20M)
Equilibrium concentration fluoride ions = ![[F^{-}]=0.117 M](https://tex.z-dn.net/?f=%5BF%5E%7B-%7D%5D%3D0.117%20M)
Molar solubility is the maximum concentration of salt present in water in ionic form beyond that no more salt will exist in its ionic form and will settle down in bottom of the solution.
The molar solubility of the solid cadmium fluoride = 0.0585 M
..[1]
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Due to addition of sodium fluoride will increase concentration of fluoride in the solution.And due to common ion effect the equilibrium will shift in backward direction in [1], that is precipitation of more cadmium fluoride.
Hence, decrease in solubility will be observed.