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Keith_Richards [23]
3 years ago
12

A 12.0 kg object is stationary on a surface that is inclined 30.0° relative to the horizontal. The coefficient of friction is 0.

65. Use a free body diagram to determine the magnitude of the force of static friction on the block.
Help please?
Physics
1 answer:
aniked [119]3 years ago
7 0

Answer:

hope you can understand the calculations

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The smallest separation resolvable by a microscope is of the order of magnitude of the wavelength used. What energy electrons wo
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Answer: a) for 150 Angstroms 6.63 *10^-3 eV; b) for 5 Angstroms 6.02 eV

Explanation: To solve this problem we have to use the relationship given by De Broglie as:

λ =p/h where p is the momentum and h the Planck constant

if we consider the energy given by acceleration tube for the electrons given by: E: e ΔV so is equal to kinetic energy of electrons p^2/2m

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replacing we obtained the above values.

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A 2 kg box of taffy candy has 40j of potential energy relative to the ground. Its height above the ground is​
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Answer:

2.04m

Explanation:

PE=mgh

h= PE/mg

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8 0
3 years ago
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Which atomic number is the threshold value below which fusion may occur?
Luda [366]

Answer:

The atomic number 26(iron) is the threshold value below which the fusion might occur.

Explanation:

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As we go up in atomic number, the energy released per nuclei goes down until it hits a minimum which is for atomic number 26 (iron) and fusion is not possible.

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What are the strength and direction of an electric field that will balance the weight of a 0.9 g plastic sphere that has been ch
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(a) The force exerted by the electric field on the plastic sphere is equal to
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where q=-3.4 nC=-3.4 \cdot 10^{-9} C is the charge of the sphere and E is the strength of the electric field. This force should balance the weight of the sphere:
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where m is the mass of the sphere and g is the gravitational acceleration.

Since the two forces must be equal, we have:
qE=mg
and so we find the intensity of the electric field
E= \frac{mg}{q}= \frac{0.9 \cdot 9.81 m/s^2}{3.4 \cdot 10^{-9} C} =2.6 \cdot 10^9 N/C

(b) Now let's find the direction of the field. The electric force must balance the weight of the sphere, which is directed downward, so the electric force should be directed upward. Since the charge is negative, the force is opposite to the electric field direction, and so the direction of the electric field is downward.
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