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QveST [7]
4 years ago
6

Compare and contrast the inner and outer planets. (Must be in complete sentences) (At least 5 sentences).

Physics
1 answer:
Karolina [17]4 years ago
8 0

To contrast inner and outer planets we will start with the climate of the planets and then move on to there lighting. To start the planets closet to the sun, mercury, venus, earth and mars, are all hot compared to the further one, jupiter, saturn, uranus, neptune. This distance also makes the farthe away planets darker than the ones closer. Now to compare all the planets vary from either gass or solid, rocky or icy. All of them spin around the sun and all have objects spinning around them, moons.

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Flauer [41]

Answer:

Dynamometer

Explanation:

We might want to use a system that calculates weight, but we would need to change it for the task, depends entirely on the task. Let 's imagine we're taking a scale to test people's weight, and you're moving it between something that moves the box and the box that are being moved, because when we push you will see the scale calculate distance. Then force until the container continues to flow.

4 0
3 years ago
Keisha writes that if an object has any external forces acting on it, then the object can be in dynamic equilibrium but not
Westkost [7]

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An object in either state of equilibrium must have no net force acting on it.

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3 years ago
Two masses are separated by a distance r. If this distance is doubled, is the force of interaction between the two masses double
baherus [9]

Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

This is mathematically represented as

<u>F= (G X m1 x m2) /r∧2</u>

where F is the force acting between the charged particles

r is the distance between the two charges measured in m

G is the gravitational constant which has a value of <em>6.674×10^-11 Nm^2 kg^-2</em>

m1 and m2 are the masses of the objects measured in Kg

Now if the distance between the is doubled then r becomes 2r. Substituting this in the above formula we get the new Force as

Force (new) = (G X m1 x m2) /(2r)∧2


Thus dividing Force(new)/Force we get

Force(new)/Force = 1/4.

Thus the gravitational force becomes 1/4th of the original value if the distance between the two masses are doubled.




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