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miss Akunina [59]
3 years ago
9

How many grams of NO can be produced from the following reaction if 68.2 grams of NO2 is consumed?

Chemistry
1 answer:
Semenov [28]3 years ago
3 0

Answer:

Option 4. 14.8 g

Explanation:

3NO2 + H2O → 2HNO3 + NO

First let us calculate the molar mass of NO2 and NO. This is illustrated below;

Molar Mass of NO2 = 14 + (2x16) = 14 + 32 = 46g/mol

Mass of NO2 from the question = 3 x 46 = 138g.

Molar Mass of NO = 14 +16 = 30g/mol

From the equation,

138g of NO2 reacted to produce 30g of NO

Therefore, 68.2g of NO2 will react to produce = (68.2 x 30)/138 = 14.8g of NO.

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7.32 moles of hydrogen reacts with 48.97 grams of nitrogen, how many moles of ammonia is produced?
faust18 [17]

3.5 moles of ammonia (NH₃) are produced

Explanation:

We have the following chemical reaction where hydrogen (H₂) reacts with nitrogen (N₂) to produce ammonia (NH₃):

3 H₂ + N₂ → 2 NH₃

number of moles = mass / molecular weight

number of moles of N₂ = 48.97 / 28 = 1.75 moles

We see from the chemical reaction that 1 mole of N₂ will react with 3 moles of H₂, so 1.75 moles of nitrogen will react with 3 × 1.75 = 5.25 moles of H₂. We have 7.32 moles of H₂, a quantity more of what is needed, so the limiting reactant is N₂.

Knowing this we devise the following reasoning:

if         1 mole of N₂ produces 2 moles of NH₃

then   1.75 moles of N₂ produces X moles of NH₃

X = (1.75 × 2) / 1 = 3.5 moles of NH₃

Learn more about:

limiting reactant

brainly.com/question/7144022

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Explanation:

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