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Fantom [35]
3 years ago
9

How does changing the number of electrons in an atom affect the atom?

Chemistry
1 answer:
Gre4nikov [31]3 years ago
4 0
In addition to protons and neutrons, all atoms have electrons, negatively charged particles that move around in the space surrounding the positively-charged nuclear core. But unlike protons, the number of electrons can and does change without affecting the kind of element an atom is!
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A balance was tested against a standard calibration mass with a certified value of 200.002 g and produced the following readings
wlad13 [49]

Answer:

Precise but not accurate.

Explanation:

We can tell the performance of the balance is precise, because the repeated measurements give values close to one another.

However, the performance of the balance is not accurate, as the mean value of the repeated measurements (195.587) is not close to the value considered as true (in this case the standard calibration mass with a certified value of 200.002 g).

7 0
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How many sig figs does 0.007 have
jeka57 [31]

Answer:

1

Explanation:

zeros are not counted when they come before a natural number

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Sergeu [11.5K]
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______ break down sugars to produce energy.
Mariana [72]

Answer:

mitochondria

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Hydrofluoric acid and Water react to form fluoride anion and hydronium cation, like this HF(aq) + H_2O(l) rightarrow F(aq) + H_3
maksim [4K]

Answer:

Kc = 1.09x10⁻⁴

Explanation:

<em>HF = 1.62g</em>

<em>H₂O = 516g</em>

<em>F⁻ = 0.163g</em>

<em>H₃O⁺ = 0.110g</em>

<em />

To solve this question we need to find the moles of each reactant in order to solve the molar concentration of each reactan and replacing in the Kc expression. For the reaction, the Kc is:

Kc = [H₃O⁺] [F⁻] / [HF]

<em>Because Kc is defined as the ratio between concentrations of products over reactants powered to its reaction coefficient. Pure liquids as water are not taken into account in Kc expression:</em>

<em />

[H₃O⁺] = 0.110g * (1mol /19.01g) = 0.00579moles / 5.6L = 1.03x10⁻³M

[F⁻] = 0.163g * (1mol /19.0g) = 0.00858moles / 5.6L = 1.53x10⁻³M

[HF] = 1.62g * (1mol /20g) = 0.081moles / 5.6L = 0.0145M

Kc = [1.03x10⁻³M] [1.53x10⁻³M] / [0.0145M]

<h3>Kc = 1.09x10⁻⁴</h3>
7 0
3 years ago
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