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4 years ago

How does acid rain affect the pH of a lake or stream

2 answers:

7 0

Acid rain have the low pH , that mean pH >7. So it will make a lake or stream be affected in the pH. Their pH will be lowed

Dimas [21]4 years ago

5 0

acidic rain water can leach aluminum from soil clay particles

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Convert 3.45 g/ml to lb/in^3

Alja [10]

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0.124639157 pounds.

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3 years ago

What does the law of conservation of matter/mass state

-Dominant- [34]

The law of conservation of mass states that mass cannot be created or destroyed. It can only be transformed/transferred from one form to another.

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3 years ago

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Which isotope has the greater mass neon-20 and neon-22

Allisa [31]

Neon-22 is the isotope with the greater mass.

P.S. When you have two isotopes of the same element, the one with the greater number will always have the greater mass

Hope that helps!

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3 years ago

Read 2 more answers

PLZ HELP "NO LINKS"

Natalka [10]

Answer: (a) Mole fraction of $H_{2}$ is 0.66.

Mole fraction of $N_{2}$ is 0.33

(b) The partial pressure of $H_{2}$ is 1.98 atm.

The partial pressure of $N_{2}$ is 0.99 atm.

(c) The total pressure is 3.0 atm

Explanation:

Given: Volume = $22.4 dm^{3}$ (1 $dm^{3}$ = 1 L) = 22.4 L

Moles of $H_{2}$ = 2.0 mol

Moles of $N_{2}$ = 1.0 mol

Total moles = (2.0 + 1.0) mol = 3.0 mol

Temperature = 273.15 K

Now, using ideal gas equation the total pressure is calculated as follows.

$PV = nRT\\$

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

$PV = nRT\\P \times 22.4 L = 3.0 mol \times 0.0821 L atm/mol K \times 273.15 K\\P = 3.0 atm$

The mole fractions of each component:

The mole fraction of $H_{2}$ is calculated as follows.

$Mole fraction = \frac{moles of H_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{2.0 mol}{(2.0 + 1.0) mol}\\= 0.66$

The mole fraction of $N_{2}$ is as follows.

$Mole fraction = \frac{moles of N_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{1.0 mol}{(2.0 + 1.0) mol}\\= 0.33$

The partial pressures of each component:

Partial pressure of $H_{2}$ are as follows.

$P_{H_{2}} = P_{total} \times mole fraction of H_{2}\\= 3.0 atm \times 0.66\\= 1.98 atm$

Partial pressure of $N_{2}$ are as follows.

$P_{N_{2}} = P_{total} \times mola fraction of N_{2}\\= 3.0 atm \times 0.33\\= 0.99 atm$

7 0

3 years ago

The acidic ingredient in vinegar is acetic acid. The pH of vinegar is around 2.4, and the molar concentration of acetic acid in

IrinaK [193]

Answer: The value of acid ionization constant $K_a$ for acetic acid is $1.87\times 10^{-5}$

Explanation:

$CH_3COOH\rightarrow H^+CH_3COO^-$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.85 M and $pH$ = 2.4

$pH=-log[H^+]$

$[H^=}=c\times \alpha=10^{-2.4}=3.98\times 10^{-3}$

$K_a=?$

Putting in the values we get:

$K_a=\frac{(3.98\times 10^{-3})^2}{(0.85-3.98\times 10^{-3})}=1.87\times 10^{-5}$

Thus the value of acid ionization constant $K_a$ for acetic acid is $1.87\times 10^{-5}$

5 0

3 years ago