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Pie
3 years ago
13

The compound gallium phosphide (Ga P) is a compound semiconductor having mixed ionic and covalent bonding. The electronegativiti

es for Ga and P are 1.6 and 2.1 respectively. Calculate the fraction of the bonding that is ionic.
Chemistry
1 answer:
alexandr1967 [171]3 years ago
5 0

Answer:  The fraction of the bonding that is ionic is 0.08875.

Explanation:

Percentage ionic character is calculated using the formula:

% ionic character =[16\times \Delta E_N + 3.5\times (\Delta E_N)^2]

Where, \Delta E_N = electronegativity difference

Given : The electronegativities for Ga and P are 1.6 and 2.1 respectively.

Thus \Delta E_N = electronegativity of phosphorous - electronegativity of galium = 2.1 -1.6 = 0.5

Therefore,

%ionic character  = [16\times 0.5 + 3.5\times (0.5)^2]=8.875

Fraction of ionic bond =\frac{8.875}{100}= 0.08875

The fraction of the bonding that is ionic is 0.08875.

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Please answer, this is due in 30 minutes
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0.591 g of magnesium phosphate is the theoretical yield.

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Explanation:

Hello!

In this case, since the balanced reaction turns out:

3Mg(NO_3)_2+2Na_3PO_4\rightarrow Mg_3(PO_4)_2+6NaNO_3

Next, we compute the grams of magnesium phosphate yielded by each reactant, considering the present mole ratios and molar masses:

m_{Mg_3(PO_4)_2}^{by\ Mg(NO_3)_2}=1.00gMg(NO_3)_2*\frac{1molMg(NO_3)_2}{148.31gMg(NO_3)_2}*\frac{1molMg_3(PO_4)_2}{3molMg(NO_3)_2}  *\frac{262.86gMg_3(PO_4)_2}{1molMg_3(PO_4)_2} \\\\m_{Mg_3(PO_4)_2}^{by\ Mg(NO_3)_2}= 0.591gMg_3(PO_4)_2\\\\m_{Mg_3(PO_4)_2}^{by\ Na_3PO_4}=1.00gNa_3PO_4*\frac{1molNa_3PO_4}{163.94gNa_3PO_4}*\frac{1molMg_3(PO_4)_2}{2molNa_3PO_4}  *\frac{262.86gMg_3(PO_4)_2}{1molMg_3(PO_4)_2} \\\\m_{Mg_3(PO_4)_2}^{by\ Na_3PO_4} = 0.802gMg_3(PO_4)_2

Thus, we infer that the correct theoretical yielded mass is 0.591 g as magnesium nitrate is the limiting reactant for which it produces the fewest grams of product.

However, is not possible to compute the percent yield since no actual yield is given, and must be provided or indicated by the problem or an experiment and it not here, nevertheless, you may compute the percent yield by dividing the actual yield by the theoretical and then multiplying by 100:

Y=\frac{actual}{0.591g}*100\%

Best regards!

4 0
3 years ago
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