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3 years ago

Solve the equation 3x^2+8x+5=0

Physics

1 answer:

Pachacha [2.7K]3 years ago

4 0

$3x^2+8x+5=0\\
3x^2+3x+5x+5=0\\
3x(x+1)+5(x+1)=0\\
(3x+5)(x+1)=0\\
x=-\dfrac{5}{3} \vee x=-1$

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In rural areas, water is often extracted from underground by pumps. Consider an underground water source whose free surface is 6

stealth61 [152]

Answer:

W = 9533.09 Watt

Explanation:

given,

diameter of pipe inlet, d₁ = 10 cm

r₁ = 5 cm

diameter of pipe outlet, d₂ = 15 cm

r₂= 7.5 cm

head upto water level is to rise = 60 + 5

= 65 m

flow rate = 0.015 m³/s

we know

A₁ v₁ = A₂ v₂ = Q

π r₁² v₁ = π r₂² v₂ = 0.015

$v_1= \dfrac{r_2^2}{r_1^2} v_2$

$v_1= \dfrac{7.5^2}{5^2} v_2$

$v_1= 2.25 v_2$

$v_2 = \dfrac{0.015}{\pi r_2^2}$

$v_2 = \dfrac{0.015}{\pi 0.075^2}$

v₂ = 0.848 m/s

v₁ = 1.908 m/s

Applying Bernoulli's equation

$P_p = \dfrac{1}{2}\rho (v_2^2-v_1^2)+ \rho g h$

$P_p= \dfrac{1}{2}\times 1000\times (0.848^2-1.908^2)+ 1000\times 9.8\times 65$

$P_p= 635539.32 Pa$

P_p is the pump pressure

Power of the pump

W = P_p x Q

W = 635539.32 x 0.015

W = 9533.09 Watt

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4 years ago

Why are hurricanes considered more damaging than tornadoes when tornadoes have stronger winds

chubhunter [2.5K]

-- A tornado follows a path that's a few miles wide, for a few hours.
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-- A hurricane follows a path that's several hundred miles wide,
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3 years ago

Read 2 more answers

Consider a spherical Gaussian surface of radius R centered at the origin. A charge Q is placed. inside the sphere. Where should

Elanso [62]

I think you forgot to give the options along with the question. I am answering the question based on my knowledge and research. "<span>The charge can be located anywhere, since flux does not depend on the position of the charge as long as it is inside the sphere" gives the answer to the question. I hope that this answer has come to your help.</span>

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3 years ago

Plz HELP

zubka84 [21]

The 2nd has the most porosity

Infiltration

That's all I can answer for you. Hope it helps

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4 years ago

Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t

zmey [24]

Answer:

+0.231 m/s

Explanation:

The problem can be solved by using the law of conservation of momentum. In fact, we have that the total momentum before the collision must be equal to the total momentum after the collision:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1 + m_2)v$