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Cloud [144]
3 years ago
6

Thickness of the filmThe UC Davis physicist measures the thickness of a layer of a benzene with nb= 1.50 by shiningmonochromatic

light onto the film and varying the wavelength of the light (the film is in the air with n= 1). She finds that the light of wavelength 635 nm is reflected most strongly from the film.
(a) What is the minimum thickness of the film?
(b) What would be the wavelength of the most reflected visible light if the same layer was placed onthe surface of water withnw= 1.3 while the laser still shines from the air.
Physics
1 answer:
ANEK [815]3 years ago
6 0

Answer:

Explanation:

  • Given λ = wavelength of light reflected = 635 nm
  • Using the equation ; 2 nb t = (m - (1/2)λ
  • nb= 1.50

Plugging the values in the equation ;

  • 2 (1.50) t = (1 - (1/2) (635)
  • t = 105.83 nm = the minimum thickness of the film

b) To calculate the wavelength of the most reflected visible light ;

  • From the equation 2 nb t = mλ
  • λ' =  2 nb t/m

Plugging the values into the equation

  • 2 (1.50) (105.83) = λ'
  • λ' = wavelength = 317.5 nm

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Explanation:

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3 years ago
What happens in the gray zone between solid and liquid?
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Answer:

Hence from liquid to solid or solid to liquid the transition has to cross the grey zone. This grey zone transition is is very crucial which includes the intermolecular forces acting on the molecules and each atoms which makes the change in state from hot to cold and cold to hot.

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3 years ago
You plug a string of 100 lights in series into a 120 V power outlet, and each light has a resistance of 3.00 _. If each light ha
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V = IR

By completing the equation, i found that the total power equation is : 4.8, 
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6 0
3 years ago
M/s
SashulF [63]

Answer:

a. Final velocity, V = 2.179 m/s.  

b. Final velocity, V = 7.071 m/s.

Explanation:

<u>Given the following data;</u>

Acceleration = 0.500m/s²

a. To find the velocity of the boat after it has traveled 4.75 m

Since it started from rest, initial velocity is equal to 0m/s.

Now, we would use the third equation of motion to find the final velocity.

V^{2} = U^{2} + 2aS

Where;

  • V represents the final velocity measured in meter per seconds.
  • U represents the initial velocity measured in meter per seconds.
  • a represents acceleration measured in meters per seconds square.
  • S represents the displacement measured in meters.

Substituting into the equation, we have;

V^{2} = 0^{2} + 2*0.500*4.75

V^{2} = 4.75

Taking the square root, we have;

V^{2} = \sqrt {4.75}

<em>Final velocity, V = 2.179 m/s.</em>

b. To find the velocity if the boat has traveled 50 m.

V^{2} = 0^{2} + 2*0.500*50

V^{2} = 50

Taking the square root, we have;

V^{2} = \sqrt {50}

<em>Final velocity, V = 7.071 m/s.</em>

8 0
3 years ago
If a sound travels 343m/s through air and has a frequency of 800Hz, what would the wavelength be of the same sound traveling thr
VARVARA [1.3K]

Answer:

0.625m

Explanation:

Now Velocity of a wave ,V = frequency × wavelength

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7 0
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