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Cloud [144]
3 years ago
6

Thickness of the filmThe UC Davis physicist measures the thickness of a layer of a benzene with nb= 1.50 by shiningmonochromatic

light onto the film and varying the wavelength of the light (the film is in the air with n= 1). She finds that the light of wavelength 635 nm is reflected most strongly from the film.
(a) What is the minimum thickness of the film?
(b) What would be the wavelength of the most reflected visible light if the same layer was placed onthe surface of water withnw= 1.3 while the laser still shines from the air.
Physics
1 answer:
ANEK [815]3 years ago
6 0

Answer:

Explanation:

  • Given λ = wavelength of light reflected = 635 nm
  • Using the equation ; 2 nb t = (m - (1/2)λ
  • nb= 1.50

Plugging the values in the equation ;

  • 2 (1.50) t = (1 - (1/2) (635)
  • t = 105.83 nm = the minimum thickness of the film

b) To calculate the wavelength of the most reflected visible light ;

  • From the equation 2 nb t = mλ
  • λ' =  2 nb t/m

Plugging the values into the equation

  • 2 (1.50) (105.83) = λ'
  • λ' = wavelength = 317.5 nm

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6 0
3 years ago
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igomit [66]

Answer:

See below

Explanation:

Find the NET forces on the objects

A  20==>

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zubka84 [21]

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4 0
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A magnifying glass has a converging lens of focal length of 13.8 cm. At what distance from a nickel should you hold this lens to
Colt1911 [192]

Answer:

19.6 cm.

Explanation:

From the question given above, the following data were obtained:

Focal length (f) = 13.8 cm

Magnification (M) = +2.37

Object distance (u) =.?

Next, we shall determine the image distance. This can be obtained as follow:

Magnification (M) = +2.37

Object distance (u) = u

Image distance (v) =?

M = v / u

2.37 = v / u

Cross multiply

v = 2.37 × u

v = 2.37u

Finally, we shall determine the object distance. This can be obtained as follow:

Focal length (f) = 13.8 cm

Image distance (v) = 2.37u

Object distance (u) =.?

1/v + 1/u = 1/f

vu / v + u = f

2.37u × u / 2.37u + u = 13.8

2.37u² / 3.37u = 13.8

Cross multiply

2.37u² = 3.37u × 13.8

2.37u² = 46.506u

Divide both side by u

2.37u² / u = 46.506u / u

2.37u = 46.506

Divide both side by 2.37

u = 46.506 / 2.37

u = 19.6 cm

Thus, the lens should be held at a distance of 19.6 cm.

7 0
3 years ago
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