3 years ago

Pls answer need help

Physics

1 answer:

igomit [66]3 years ago

6 0

Answer:

See below

Explanation:

Find the NET forces on the objects

A 20==>

B 0

C 30==>

D 15==>

So biggest accel = C because it has the most force acting on it

next is A because it has the next biggest force

next is D then B ...B has no net force acting on it

You might be interested in

Convert (a) 50 oF, (b) 80 oF, (c) 95 oF to Celsius

storchak [24]

I really need these points thx a lot

5 0

3 years ago

Which of the following is not a symptom associated with hypertension

Romashka-Z-Leto [24]

Do you have any answer choices?

3 0

3 years ago

Two students 8 meters apart are holding a stretched, coiled spring between them. One student sends a pulse down the string, and

IgorC [24]

Answer:

Explanation:

Distance travelled by wave = 8 x 2 = 16 m

Time taken = 4 s

velocity of pulse wave = distance / time

= 16 m / 4 s

= 4 m/s

8 0

3 years ago

You want to manufacture a guitar such that the instrument will be in tune when each of the strings are tightened to the same ten

charle [14.2K]

Answer:

0.000507 kg/m

Explanation:

L = Length of string

T = Tension

$\mu$ = Mass density of string

E denotes the E string

D denotes the D String

Frequency is given by

$f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}$

$f\propto \sqrt{\dfrac{1}{\mu}}$

$\dfrac{f_D}{f_E}=\sqrt{\dfrac{\mu_E}{\mu_D}}\\\Rightarrow \mu_E=\dfrac{f_D^2}{f_E^2}\mu_D\\\Rightarrow \mu_E=\dfrac{146.83^2}{329.63^2}\times 0.00256\\\Rightarrow \mu_E=0.000507\ kg/m$

The mass density of the E string is 0.000507 kg/m

8 0

3 years ago

Helium atoms have a mass of 4u and oxygen molecules have a mass of 32u, where u is defined as an atomic mass unit (u=1.660540 x

Elden [556K]

Answer:

300 K

37.5 K

Explanation:

$k_b$ = Boltzmann constant = $1.38\times 10^{-23}\ J/K$

T = Absolute temperature

$M_h$ = Mass of Helium atom = 4 u

$M_o$ = Mass of Oxygen atom = 32 u

$u=1.660540\times 10^{−27}\ kg$

The kinetic energy of a gas is given by

$K=\frac{3}{2}k_bT$

So, the temperature would be 300 K

RMS velocity is given by

$v=\sqrt{\frac{3k_bT}{M}}$

$\frac{T_h}{M_h}=\frac{T_o}{M_o}\\\Rightarrow T_h=\frac{T_o}{M_o}\times M_h\\\Rightarrow T_h=\frac{300\times 4}{32}\\\Rightarrow T_h=37.5\ K$

The gas temperature is 37.5 K

5 0

3 years ago