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insens350 [35]
3 years ago
11

Pls answer need help

Physics
1 answer:
igomit [66]3 years ago
6 0

Answer:

See below

Explanation:

Find the NET forces on the objects

A  20==>

B    0

C  30==>

D  15==>    

So biggest accel = C because it has the most force acting on it

 next is A because it has the next biggest force

    next is  D        then    B ...B has no net force acting on it  

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1. A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly hori
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The net acceleration of the SUV is 0.429 meters per square second due west.

Explanation:

Statement is incomplete. Description is presented below:

<em>A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly horizontal road. The surface of the road exerts a resistance force of 500 N due east. At the same time a high wind is blowing a force of 500 N due east in the opposite direction of the car's drive force. Does the car has any acceleration? If yes, then what are the magnitude and direction of the car's acceleration?</em>

According to Newton's Laws of Motion, the SUV will accelerate if and only if net acceleration is different of zero. Let suppose as positive the direction of driving force (F), measured in newtons:

\Sigma F = F - R -f = F_{net} (1)

Where:

R - Resistance force, measured in newtons.

f - Wind force, measured in newtons.

F_{net} - SUV net force, measured in newtons.

If we know that F = 2500\,N, R = 500\,N and f = 500\,N, then net force experimented by the SUV is:

F_{net} = 2500\,N-500\,N-500\,N

F_{net} = 1500\,N

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By definition of force for systems with constant mass, we calculate the acceleration of the vehicle below:

a_{net} = \frac{F_{net}}{m} (2)

Where m is the mass of the SUV, measured in kilograms.

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a_{net} = \frac{1500\,N}{3500\,kg}

a_{net} = 0.429\,\frac{m}{s^{2}}

The net acceleration of the SUV is 0.429 meters per square second due west.

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