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3 years ago

5

A what is marked by two sets of double yellow lines with each set having a broken line on the inside and a solid line on the out

side A ) merge lanes B) HOV lanes C) Center left turn lanes D) Center right turn lanes

1 answer:

yKpoI14uk [10]3 years ago

5 0

Answer:

(C) Center left turn lanes!

Explanation:

I'm positive this answer is correct! :)

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3. (a) (5 points) Suppose N packets arrive simultaneously to a link at which no packets are currently being transmitted or queue

Bezzdna [24]

Answer:

(N-1) × (L/2R) = (N-1)/2

Explanation:

let L is length of packet

R is rate

N is number of packets

then

first packet arrived with 0 delay

Second packet arrived at = L/R

Third packet arrived at = 2L/R

Nth packet arrived at = (n-1)L/R

Total queuing delay = L/R + 2L/R + ... + (n - 1)L/R = L(n - 1)/2R

Now

L / R = (1000) / (10^6 ) s = 1 ms

L/2R = 0.5 ms

average queuing delay for N packets = (N-1) * (L/2R) = (N-1)/2

the average queuing delay of a packet = 0 ( put N=1)

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4 years ago

What ic engine for mechanic

stealth61 [152]

Answer: There are two kinds of internal combustion engines currently in production: the spark ignition gasoline engine and the compression ignition diesel engine. Most of these are four-stroke cycle engines, meaning four piston strokes are needed to complete a cycle.

Explanation:

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3 years ago

A thick casting with a thermal diffusivity of 5 x 10-6 m2/s is initially at a uniform temperature of 150oC. One surface of the c

fredd [130]

Answer:

$T_o = 141.81 ^0C$

Explanation:

Given that;

Thermal diffusivity $\alpha = 5 \times 10 ^{-6} m^2/s$

Thermal conductivity $k = 20 \ W/m.K$

Heat transfer coefficient h = ( we are to assume the imposed surface temperature ) = 20 W/m².K

Initial temperature = 150 ° C = (150+273) K = 423 K

Then coolant temperature with which the casting is exposed to = 20° C = (20+273)K = 293 K

Time = 40 seconds

Length = 20mm = 0.02 m

The objective is to determine the temperature at the surface at a depth of 20 mm after 40 seconds.

$Bi = \dfrac{hL}{k}$

$Bi = \dfrac{20*0.02}{20}$

Bi == 0.02

$\tau = \dfrac{\alpha t}{L^2}$

$\tau= \dfrac{5*10^{-6 }* 40}{0.020^2}$

$\tau = 0.5$

For a wall at 0.2 Bi

$A_1 = 1.0311$

$\lambda _1 = 0.4328$

Therefore;

$\dfrac{T_o - T_{\infty}}{T_i - T_{\infty}}= A_1 e ^{-( \lambda_1^2 \ \tau)$

$\dfrac{T_o - 293 }{423 - 293}= 1.0311 \times e ^{-( 0.438^2 \times 0.5 )$

$\dfrac{T_o - 293 }{423 - 293}= 1.0311 \times e ^{-( 0.0959 )$

$\dfrac{T_o - 293 }{130}= 1.0311 \times 0.9085$

$\dfrac{T_o - 293 }{130}= 0.937$

$T_o - 293= 0.937 \times 130$

$T_o - 293= 121.81$

$T_o = 121.81+ 293$

$T_o = 414.81 \ K$

$T_o = (414.81 - 273)^0C$

$T_o = 141.81 ^0C$

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4 years ago

What device may be used to ensure that air is flowing through a duct before an electric strip is energized

andriy [413]

Answer:

Most commonly used air flow proving interlocks are:

differential pressure air flow switch. Contact changes state based on duct static vs. atmosphere outside the duct or dp across a fan inlet to outlet
CT relay. Current transformer relay that changes state from 0 to 1 open/closed when amp draw on a blower motor exceeds the trip setpoint.

Explanation:

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3 years ago

In 2001, a land-development company launched an engineering project on land adjacent to a protected wetlands area

mart [117]

The statement that summarizes the data is that the population data should be collected over a much lingers period of time in order rot draw a valid conclusion.

<h3>What is data?</h3>

It should be noted that data simply means the facts or statistics that are put together to get more information about a particular issue.

In this case, the statement that summarizes the data is that the population data should be collected over a much lingers period of time in order rot draw a valid conclusion.

Learn more about data on:

brainly.com/question/4219149

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5 0

2 years ago