Answer:
A recrystallization process differs mainly from a restoration process (microestructures of a cold worked sample) in that the first, the microstructure of the final product consists mainly of high angle borders.
Explanation:
The microstructure of a cold worked material has a high energy stored in dislocations and subgrains. During a heat treatment, this microstructure evolves in order to achieve a more stable state by reducing its energy. The complex microscopic mechanisms that take place during this process have been traditionally encompassed in three categories: restoration, recrystallization and grain growth, which will be discussed later.
These processes generally lead to the total or partial recovery of the original properties of the material (ductility, resistance). They can take place under dynamic conditions, that is, during thermomechanical processing or when the material is subsequently deformed at high temperature, and under static conditions, that is, during a heat treatment after thermomechanical processing.
The term <em>restoration</em> encompasses the following succession of micromechanism: formation of dislocation cells, annihilation of dislocations within them, formation of subgrains and their growth.
<em>A recrystallization process differs mainly from a restoration process in that in the first one the microstructure of the final product is mainly formed by high-angle borders.</em>
Answer:
The total hole mobility is 41.67 cm²/V s
Explanation:
Data given by the exercise:
hole mobility due to lattice scattering = ul = 50 cm²/V s
hole mobility due to ionized impurity = ui = 250 cm²/V s
The total mobility is equal:
Answer:
<h2>698.3Kpa</h2>
Explanation:
Step one:
given data
V1=0.25m^3
T1=290k
P1=100kPa
V2=0.5m^2
T2=405k
P2=? final pressure
Step two:
The combined gas equation is given as
P1V1/T1=P2V2/T2
Substituting we have
(100*0.25)/290=P2*0.05/405
25/290=0.5P2/405
0.086=0.05P2/405
cross multiply
0.086*405=0.05P2
34.9=0.05P2
divide both sides by 0.05
P2=34.9/0.05
P2=698.3Kpa
<u>Therefore the new pressure is 698.3Kpa when the gas is compressed</u>
Answer:
Option A
Explanation:
We know that ions are present in hydrogen-air flame and when the burning of an organic compound takes place in this flame more ions are produced in the flame.
Thus when we apply a voltage across this flame, the ion collector plate attracts the all the ions in the flame.
The presence of organic compounds increases the voltage across the hydrogen ion flame produced at the ion collector increases and as the voltage increases, the detection of the organic compound can be made in turn.
Thus flame ionization detector clearly responds to the variation in the collection of ions or electrons in a flame.
Answer:
a mass of water required is mw= 1273.26 gr = 1.27376 Kg
Explanation:
Assuming that the steam also gives out latent heat, the heat provided should be same for cooling the hot water than cooling the steam and condense it completely:
Q = mw * cw * ΔTw = ms * cs * ΔTw + ms * L
where m = mass , c= specific heat , ΔT=temperature change, L = latent heat of condensation
therefore
mw = ( ms * cs * ΔTw + ms * L )/ (cw * ΔTw )
replacing values
mw = [182g * 2.078 J/g°C*(118°C-100°C) + 118 g * 2260 J/g ] /[4.187 J/g°C * (90.7°C-39.4°C)] = 1273.26 gr = 1.27376 Kg
