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zhenek [66]
3 years ago
15

How many moles of calcium chloride (CaCl2) are needed to react completely with 6.2 moles of silver nitrate (AgNO3)? 2AgNO3 + CaC

l2 → 2AgCl + Ca(NO3)2
A. 2.2 mol CaCl2

B. 3.1 mol CaCl2

C. 6.2 mol CaCl2

D. 12.4 mol CaCl2
Chemistry
1 answer:
nexus9112 [7]3 years ago
6 0

Here we have to choose the right option which tells the moles of CaCl₂ will react with 6.2 moles of AgNO₃ in the reaction

2AgNO₃ + CaCl₂→ 2AgCl + Ca(NO₃)₂

6.2 moles of silver nitrate (AgNO₃) will react with B. 3.1 moles of calcium chloride (CaCl₂).

From the reaction: 2AgNO₃ + CaCl₂→ 2AgCl + Ca(NO₃)₂

Thus 2 moles of AgNO₃ reacts with 1 mole of CaCl₂

Henceforth, 6.2 moles of AgNO₃ reacts with \frac{6.2}{2} = 3.1 moles of CaCl₂.

1 mole of CaCl₂ reacts with 2 moles of AgNO₃. Thus-

A. 2.2 moles of CaCl₂ will react with 2.2×2 = 4.4 moles of AgNO₃.

C. 6.2 moles of CaCl₂ will reacts with 6.2×2 = 12.4 moles of AgNO₃.

D. 12.4 moles of CaCl₂ will reacts with 12.4 × 2 = 24.8 moles of AgNO₃

Thus the right answer is 6.2 moles of AgNO₃ will react with 3.1 moles of CaCl₂.

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allsm [11]

Answer:

2CO₂ ⇄ 2CO + O₂.

Explanation:

  • <em>The equilibrium constant (Keq)</em> for a reaction is the ratio of the concentration of the products to the reactants, each one is raised to each molar coefficient.

So, for Keq = [CO]²[O₂]/[CO₂]²,

It is clear that the products are CO and O₂, while the reactant is CO₂.

So, the reaction for this is:

<em>2CO₂ ⇄ 2CO + O₂.</em>

7 0
3 years ago
For this reaction, C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ. If two moles of C3H8(g) reacted with excess oxygen,
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A) 4400 kj of heat released into surroundings

<h3>Further explanation</h3>

Reaction

C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ

Reaction exothermic( ∆H=-, released heat to surrounding) and for combustion of 1 mole of C3H8

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Explanation:

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El porcentaje en volumen (%v/v) expresa el volumen de soluto (alcohol en este caso) que hay cada 100 mL de solución. Si la solución tiene una concentración del 4,5% v/v eso quiere decir que hay 4,5 ml de alcohol cada 100 ml de solución, de acuerdo a lo siguiente:

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